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Svetllana [295]
3 years ago
13

For the function f(x) = (5-6x)^2, fine f^-1

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
8 0

Answer:

f(-1) = 121

Step-by-step explanation:

f(x) = (5-6x)^2 (First we will substitute x for -1)

f(-1) = (5-6(-1))^2 (Then we will combine like terms)

f(-1) = (11)^2 (Then we will square it)

f(-1) = 121 (You are done)

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(-17) x (-46) =<br> find the product
alina1380 [7]

Answer:

782

Step-by-step explanation:

Hope this helps

4 0
3 years ago
Step by Step <br><br> If 35% of a number is 40, what is the number?
zheka24 [161]
.35x=40
/.35 /.35
X= 40/.35
X = 114.2857
4 0
3 years ago
The Cheer Club is making a banner for your school using the design shown. The area of the yellow portion is 1 ft2. The expressio
olga nikolaevna [1]

Answer:

Blue = \frac{8}{9}

Step-by-step explanation:

Given

Yellow = 1ft^2

Blue = 8z^{-1

Required

Evaluate Blue when z = 9

To do this, we simply substitute 9 for z in Blue = 8z^{-1

Blue = 8 * 9^{-1

Convert indices to fraction

Blue = 8 * \frac{1}{9}

Blue = \frac{8}{9}

<em>Hence, the blue section has an area of </em>\frac{8}{9}ft^2<em></em>

3 0
3 years ago
Find the equation of the sphere if one of its diameters has endpoints (4, 2, -9) and (6, 6, -3) which has been normalized so tha
Pavel [41]

Answer:

(x - 5)^2 + (y - 4)^2 + (z - 6)^2 = 14.

(Expand to obtain an equivalent expression for the sphere: x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0)

Step-by-step explanation:

Apply the Pythagorean Theorem to find the distance between these two endpoints:

\begin{aligned}&\text{Distance}\cr &= \sqrt{\left(x_2 - x_1\right)^2 + \left(y_2 - y_1\right)^2 + \left(z_2 - z_1\right)^2} \cr &= \sqrt{(6 - 4)^2 + (6 - 2)^2 + ((-3) - (-9))^2 \cr &= \sqrt{56}}\end{aligned}.

Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:

\begin{aligned} r &= \frac{1}{2} \, \sqrt{56} \cr &= \sqrt{\left(\frac{1}{2}\right)^2 \times 56} \cr &= \sqrt{\frac{1}{4} \times 56} \cr &= \sqrt{14} \end{aligned}.

In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between \left(x_1, \, y_1, \, z_1\right) and \left(x_2, \, y_2, \, z_2\right) would be:

\displaystyle \left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right).

In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:

\begin{aligned}&\left(\frac{x_1 + x_2}{2},\, \frac{y_1 + y_2}{2}, \, \frac{z_1 + z_2}{2}\right) \cr &= \left(\frac{4 + 6}{2},\, \frac{2 + 6}{2}, \, \frac{(-9) + (-3)}{2}\right) \cr &= (5,\, 4\, -6)\end{aligned}.

The equation for a sphere of radius r and center \left(x_0,\, y_0,\, z_0\right) would be:

\left(x - x_0\right)^2 + \left(y - y_0\right)^2 + \left(z - z_0\right)^2 = r^2.

In this case, the equation would be:

\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z - (-6)\right)^2 = \left(\sqrt{56}\right)^2.

Simplify to obtain:

\left(x - 5\right)^2 + \left(y - 4\right)^2 + \left(z + 6\right)^2 = 56.

Expand the squares and simplify to obtain:

x^2 - 10\,x + y^2 - 8\, y + z^2 - 12\, z + 63 = 0.

8 0
3 years ago
There are 120 children standing in a line, every third child gets a rubber, every fourth child gets a ruler and every fifth chil
nevsk [136]

Answer:

It would be the 60th child

Step-by-step explanation:

3,6,9,12,

4,8,12,16,

5,10,15,

60 is the first number that can be divided by 60/3=20 60/4=15 60/5=12

Hope this helps<3

6 0
2 years ago
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