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Svetllana [295]
3 years ago
13

For the function f(x) = (5-6x)^2, fine f^-1

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
8 0

Answer:

f(-1) = 121

Step-by-step explanation:

f(x) = (5-6x)^2 (First we will substitute x for -1)

f(-1) = (5-6(-1))^2 (Then we will combine like terms)

f(-1) = (11)^2 (Then we will square it)

f(-1) = 121 (You are done)

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Answer:

So \frac{x^2-12x+8}{x-5}=(x-7)+\frac{-27}{x-5}

Step-by-step explanation:

Since we are dividing by a linear factor, I'm going to use synthetic division.

Since the linear factor that we are dividing by is (x-5), I'm going to put 5 on the outside:

5    |     1       -12       8

      |              5      -35

      |--------------------------

           1         -7      -27

So the quotient x-7 while the remainder is -27.

So \frac{x^2-12x+8}{x-5}=(x-7)+\frac{-27}{x-5}

You could do long division if you prefer:

           x-7

         ------------------------

(x-5) |   x^2-12x+8

        - (x^2-5x)

        --------------------------

                -7x+8

              -(-7x+35)

         ---------------------

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You still get the same thing that the quotient is x-7 and the remainder is -27.

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Please show work to thank you​
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Answer:

Step-by-step explanation:

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3) ∠ADB and ∠CDB are right angles              3) perpendicular bisector thm.

4) ∠ADB ≅ ∠CDB                                             4) all right ∡'s are congruent

5) BD ≅ BD                                                       5) reflexive POV

6) ΔABD ≅ ΔCBD                                             6) SAS

Hope this helps!

btw, I was not able to put the lines on top of some of the letters, so my apologies.

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