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shutvik [7]
3 years ago
6

The average radius of a molecule of lysozyme, an enzyme in tears, is 1.430 *10^-3 um. What is its radius in millimeter? Enter yo

ur answer in scientific notation.
Chemistry
2 answers:
Nezavi [6.7K]3 years ago
5 0
Basically, this problem tells you to convert micrometers (μm) to millimeters (mm). The prefixes are used as hints for their values. Micrometer is 10⁻⁶ of a meter, while millimeter is 10⁻³ of a meter. If you use dimensional analysis,

(1.430×10⁻³ μm)*(10⁻⁶ m/1 μm)*(1 mm/10⁻³ m) = 1.43×10⁻⁶ mm
Aleonysh [2.5K]3 years ago
3 0

The average radius of a molecule of lysozyme (in millimeter) is \boxed{1.430 \times {{10}^{ - 6}}{\text{ mm}}}.

Further Explanation:

The comparison between measurements is performed with the help of some standards which are known as units. Units are of two types-basic and derived. Basic units do not require any other unit to express themselves but derived units need fundamental units to describe them. Basic units are mass, length and temperature but density, area, and volume are derived units.

Conversion factors are the ratios that are expressed in the form of fractions and are used to convert one unit into another.

The average radius of the lysozyme molecule is 1.430 \times {10^{ - 3}}{\text{ }}\mu {\text{m}}. It is to be converted from  to mm. The conversion factor for this is given as follows:

1{\text{ }}\mu {\text{m}} = {10^{ - 3}}{\text{ mm}}

Therefore the average radius of the lysozyme molecule can be calculated as follows:

\begin{aligned}{\text{Average radius of lysozyme molecule}} &= \left( {1.430 \times {{10}^{ - 3}}{\text{ }}\mu {\text{m}}} \right)\left( {\frac{{{{10}^{ - 3}}{\text{ mm}}}}{{1{\text{ }}\mu {\text{m}}}}} \right)\\&= 1.430 \times {10^{ - 6}}{\text{ mm}} \\\end{aligned}  

Therefore the average radius of a molecule of lysozyme is 1.430 \times {10^{ - 6}}{\text{ mm}}.

Learn more:

  1. What is the mass of 1 mole of viruses: brainly.com/question/8353774
  2. Determine the moles of water produced: brainly.com/question/1405182

Answer details:

Grade: Senior School

Chapter: Basic concepts of chemistry

Subject: Chemistry

Keywords: unit, basic units, derived units, average radius, lysozyme molecule, 1.430*10^-6 mm, conversion factor, mass, length, temperature, density, volume, area, comparison, measurements, ratios, fractions, standards.

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Explanation:

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How many grams of solid NaOH are required to prepare a 400ml of a 5N solution? show your work!
Nuetrik [128]

<u>Answer:</u> The mass of solid NaOH required is 80 g

<u>Explanation:</u>

Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:

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Putting values in above equation, we get:

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Or,

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We are given:

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Putting values in equation 1, we get:

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