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IRINA_888 [86]
3 years ago
8

n the laboratory, two forms of sodium phosphate will be available (the monobasic monohydrate NaH2PO4·H2O, F.W. = 137.99 g/mol, a

nd the dibasic Na2HPO4, F.W. = 141.96 g/mol). Explain the most efficient way of making this phosphate buffer by using only one of the compounds, and specify which compound you will use.
Chemistry
1 answer:
const2013 [10]3 years ago
6 0

Answer:

The compound you will use is the Dibasic phosphate

Explanation:

Simple phosphate buffer is used ubiquitously in biological experiments, as it can be adapted to a variety of pH levels, including isotonic. This wide range is due to phosphoric acid having 3 dissociation constants, (known in chemistry as a triprotic acid) allowing for formulation of buffers near each of the pH levels of 2.15, 6.86, or 12.32. Phosphate buffer is highly water soluble and has a high buffering capacity,

In this case the most efficient way is to disolve the dibasic compound which in the reaction with the water will form the monobasic phosphate.

To make the buffer you have to prepare the amount of distillate water needed, disolve the dibasic phospate, and then adjust with HCl or NaOH depending on the pH needed.

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Density is a derived unit of mass / volume.
lapo4ka [179]

Answer:

1kg/L

Explanation:

1.) convert grams to kilograms

1000g÷1000=1kg

2.)use formula to find density

density =  \frac{mass}{volume}

= 1kg/1.0L

=1kg/L

6 0
2 years ago
1.Bubbling or fizzing is an indicator of
hodyreva [135]
D is the answer since it is changing the element.
6 0
3 years ago
What is the concentration of a solution that has 15.0 g NaCl dissolved to a total of 750 ml?
Oksana_A [137]

<u>Answer:</u> The concentration of solution is 0.342 M

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (Sodium chloride) = 15 g

Molar mass of sodium chloride = 58.5 g/mol

Volume of solution = 750 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{15g\times 1000}{58.5g/mol\times 750mL}\\\\\text{Molarity of solution}=0.342M

Hence, the concentration of solution is 0.342 M

6 0
3 years ago
If I add 475mL of water to 75.0mL of a 0.315M NaOH solution, what will the molarity of the diluted solution be?
pantera1 [17]
Answer is: <span>the molarity of the diluted solution 0,043 M.
</span>V(NaOH) = 75 mL ÷ 1000 mL/L = 0,075 L.
c(NaOH) = 0,315 M = 0,315 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,075 L · 0,315 mol/L.
n(NaOH) = 0,023625 mol.
V(solution) = 0,475 L + 0,75 L.
c(solution) = 0,023625 mol ÷ 0,550 L.
c(solution) = 0,043 mol/L.
5 0
4 years ago
. How many ethyl groups are in the molecule 3, 3-diethylpentane?
Mamont248 [21]

Answer:

2 groups

Explanation:

The molecule 3, 3-diethylpentane has 2 ethyl groups because the prefix di- means that there are 2 homogeneous substituent groups present in the molecule.

6 0
2 years ago
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