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Rudiy27
3 years ago
14

50.0 mL of an HNo3 solution were titrated with 36.90 mL of a 0.100 M LiOH solution to reach the equivalence point. What is the m

olarity of the HNO3 solution.
Chemistry
1 answer:
sleet_krkn [62]3 years ago
3 0
Answer: 0.0738 M

Explanation:


1) Chemical equation:

<span>HNO₃ + LiOH → LiNO₃ + H₂O
</span>

2) Mole ratios:

1 mol HNO₃ neutralizes 1 mol LiOH

3) Number of moles of H⁺ from HNO₃:

M = n / V ⇒ n = M × V = 0.050 liter × M

4) Number of moles of OH⁻ from LiOH

M = n / V ⇒ n = M × V = 0.03690 liter × 0,100 M

5) Equivalence point:

number of moles of H⁺ = number of moles of OH⁻

⇒ 0.0500 × M = 0.03690 × 0.100 

⇒ M = 0.03690 × 0.100 / 0.0500 = 0.0738 M
<span />
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if the mass of 191 grams NaCl reacted with 74 frams of calcium hydroxide and 80 grams of sodium hydroxide is produced, what mass
nadya68 [22]
<h3>Answer:</h3>

110.98 g/mol

<h3>Explanation:</h3>

The reaction between NaCl and Ca(OH)₂ is given by the equation;

2NaCl(aq) + Ca(OH)₂(s) → 2NaOH(aq) + CaCl₂(aq)

We are required to determine the mass of CaCl₂ produced,

We will use the following simple steps;

Step 1: Moles of NaCl and Ca(OH)₂ given

Number of moles = Mass ÷ Molar mass

Moles of NaCl

Mass of NaCl = 191 g

Molar mass NaCl = 58.44 g/mol

Number of moles = 191 g ÷ 58.44 g/mol

                             = 3.268 moles

                             = 3.27 Moles

Moles of Ca(OH)₂

Mass of Ca(OH)₂ = 74 g

Molar mass of Ca(OH)₂ = 74.093 g/mol

Number of moles = 74 g ÷ 74.093 g/mol

                             = 0.998 mole

                              = 1.0 mole

However, from the equation  2 moles of NaCl requires 1 mole of Ca(OH)₂

Therefore, from the amount of reactants available NaCl was in excess and Ca(OH)₂ is the limiting reactant .

Step 2: Moles of CaCl₂ produced

From the equation

1 mole of Ca(OH)₂ reacts with NaCl to produce 1 mole of CaCl₂

Therefore; the mole ratio of Ca(OH)₂ to CaCl₂ is 1: 1

Thus;

Moles of CaCl₂ produced is 1.0 moles

Step 3: Mass of CaCl₂ produced

Moles of CaCl₂ = 1.0 mole

Molar mass CaCl₂ = 110.98 g/mol

But; mass = number of moles × Molar mass

Therefore;

Mass of CaCl₂ = 1.0 mole × 110.98 g/mol

                       = 110.98 g CaCl₂

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2 years ago
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