Question

Hi There! Can someone please help me with this Maths Question as soon as possible. I will mark the brainliest. Write each calculation as a single power. a) 8^5 multiplied by 8^4 b) 3^11 multiplied by 3 c)9^3 multiplied by 9^7 multiplied by 9^6 d) 7^7 ÷ 7 e) 12^10 ÷ 12^5 f) (6^3)^6

Answer 1

I'll be using the following properties about exponents:

$a^b \times a^c=a^{b+c}$

$a^b \div a^c=a^{b-c}$

$(a^b)^c=a^{bc}$

where a, b, and c are some positive integers

Part a:

$8^5 \times 8^4 = 8^{5+4}=8^9$

Part b:

$3^{11} \times 3 = 3^{11} \times 3^{1} = 3^{11+1} = 3^{12}$

Part c:

$9^3 \times 9^7 = 9^{3+7}=9^{10}$

Part d:

$7^7 \div 7 = 7^7 \div 7^1 = 7^{7-1}=7^6$

Part e:

$12^{10} \div 12^5 = 12^{10-5}=12^5$

Part f:

$(6^3)^6 = 6^{6 \times 3} = 6^{18}$

These should be all the answers. Let me know if you need any clarifications, thanks!