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2 years ago

A solution is prepared by dissolving 15 grams of sugar in 85 grams of water. How many percent of sugar is in the solution?

Chemistry

1 answer:

trasher [3.6K]2 years ago

7 0

Answer:

15%

Explanation:

From the question given above, the following data were obtained:

Mass of sugar = 15 g

Mass of water = 85 g

Percentage of sugar in the solution =?

Next, we shall determine the mass of the solution. This can be obtained as follow:

Mass of solute (sugar) = 15 g

Mass of solvent (water) = 85 g

Mass of solution =?

Mass of solution = mass of solute + mass of solvent

Mass of solution = 15 + 85

Mass of solution = 100 g

Finally, we shall determine the percentage of the sugar in the solution. This can be obtained as follow:

Mass of solute (sugar) = 15 g

Mass of solution = 100 g

Percentage of sugar in the solution =?

Percentage = solute /solution × 100

Percentage = 15 / 100 × 100

Percentage of sugar in the solution = 15%

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2 years ago

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Why?

In order to calculate how many milliliters are needed to obtain 16.1 grams of the salt given its concentration, we first need to find its chemical formula which is the following:

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Now that we know the chemical formula of the substance, we need to find its molecular mass. We can do it by the following way:

$N_{2}=14g*2=28g\\\\2H_{4}=2*1g*4=8g\\\\C=12.01g*1=12.01g\\\\O_{3}=15.99g*3=47.97g$

We have that the molecular mass of the substance will be:

$MolecularMass=\frac{28g+8g+12.01g+47.97g}{mol}=95.98\frac{g}{mol}$

Therefore, knowing the molecular mass of the substance, we need to calculate how many mols represents 16.1 grams of the same substance, we can do it by the following way:

$mol_{(NH_{4})2CO_{3}=\frac{mass_{(NH_{4})2CO_{3}}}{molarmass_{(NH_{4})2CO_{3}}}$

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Finally, if we need to calculate how many milliliters are needed, we need to use the following formula:

$M=\frac{moles_{solute}}{volume_{solution}}$

$M=\frac{moles_{solute}}{volume_{solution}}\\\\volume_{solution}=\frac{moles_{solute}}{M}$

Now, substituting and calculating, we have:

$volume_{solution}=\frac{0.167mol}{0.170\frac{mol}{L}}\\\\volume_{solution}=0.982L=0.982L*1000=982.35mL$

Henc, there will be needed 982.35 mL of solution to obtain 16.1 grams of the salt.

Have a nice day!

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