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3 years ago

A solution is prepared by dissolving 15 grams of sugar in 85 grams of water. How many percent of sugar is in the solution?

Chemistry

1 answer:

trasher [3.6K]3 years ago

7 0

Answer:

15%

Explanation:

From the question given above, the following data were obtained:

Mass of sugar = 15 g

Mass of water = 85 g

Percentage of sugar in the solution =?

Next, we shall determine the mass of the solution. This can be obtained as follow:

Mass of solute (sugar) = 15 g

Mass of solvent (water) = 85 g

Mass of solution =?

Mass of solution = mass of solute + mass of solvent

Mass of solution = 15 + 85

Mass of solution = 100 g

Finally, we shall determine the percentage of the sugar in the solution. This can be obtained as follow:

Mass of solute (sugar) = 15 g

Mass of solution = 100 g

Percentage of sugar in the solution =?

Percentage = solute /solution × 100

Percentage = 15 / 100 × 100

Percentage of sugar in the solution = 15%

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Design an experiment to collect data that supports the claim that a 1.0M NaCl solution is a homogenous mixture.

Alika [10]

The claim is that NaCl mixture is a homogeneous mixture.
Homogeneous mixture means that the components of the mixtures cannot be determined or separated by the naked eye. However, these components can be separated using physical means, such as boiling, evaporation and condensation which will be used in this experiment.

First, we need to prepare one molar solution of NaCl. To do so, we will dilute a mass of 58.44 grams (molar mass of NaCl) in 1 liter of water.
By this, we will have NaCl solution.

We can notice that once the NaCl is diluted in water, all what you can see is a clear solution. You cannot see the separate particles of NaCl in water.
..............> observation I

Now, we will heat this solution until it boils and water starts evaporating. We will place a cold surface above the steam coming out from the boiling solution.

What we will observe is that when all the water evaporates, we can see white precipitate of NaCl in the bottom of the container. Examining the cold surface placed above the steam, we can see that the water has condensed on this surface.
.........>observation II

Based on this, we managed to use boiling, evaporation and condensation (physical methods) to restore the components of the solution separately.
.............>conclusion

Based on observation I, observation II and the conclusion. we were able to prove that NaCl solution is a homogeneous mixture.

7 0

3 years ago

agcl molar masA 250.0 g sample of a white solid is known to be a mixture of KNO3, BaCl2, and NaCl. When 100.0 g of this mixture

tatiyna

Answer:

a. BaSO₄ and AgCl.

b. 150.0g of BaCl₂, 50.0g of NaCl and 50.0g of KNO₃

Explanation:

Barium, Ba, from BaCl₂ reacts with the SO₄²⁻ of H₂SO₄ to produce BaSO₄, an insoluble white salt.

The reaction is:

BaCl₂ + H₂SO₄ → BaSO₄ + 2HCl

Also, Chlorides from BaCl₂ (2Cl⁻) and NaCl (1Cl⁻) react with AgNO₃ to produce AgCl, another white insoluble salt, thus:

Cl⁻ + AgNO₃ → AgCl + NO₃⁻

a. Thus, formulas of the two precipitates are: BaSO₄ and AgCl

b. Moles of BaSO₄ in 67.3g (Molar mass BaSO₄: 233.38g/mol) are:

67.3g × (1 mol / 233.38g) = 0.2884 moles of BaSO₄ = moles of BaCl₂ Because 1 mole of BaCl₂ produces 1 mole of BaSO₄

Now, as molar mass of BaCl₂ is 208.23g/mol, the mass of BaCl₂ in the mixture of 100.0g is:

0.2884 moles of BaCl₂ ₓ (208.23g /mol) = 60.0g of BaCl₂ in 100g of the mixture

Moles of the AgCl produced (Molar mass AgCl: 143.32g/mol) are:

197.96g ₓ (1mol / 143.32g) = 1.38 moles of AgCl.

As moles of Cl⁻ that comes from BaCl₂ are 0.2884 moles×2×1.5 (1.5 because the sample is 150.0g not 100.0g as in the initial reaction)

= 0.8652 moles of BaCl₂, that means moles of NaCl are:

1.38mol - 0.8652mol = 0.5148 moles of NaCl (Molar mass 58.44g/mol):

Mass NaCl in 150g =

0.5148mol NaCl × (58.44g/mol) = 30.0g of NaCl in 150.0g

That means, in the 250.0g of sample, the mass of BaCl₂ is:

60.0g BaCl₂ ₓ (250.0g / 100g) = 150.0g of BaCl₂

Mass of NaCl is:

30.0g NaCl ₓ (250.0g / 150g) = 50.0g of NaCl

As the total mass of the mixture is 250.0g, the another 50.0g must come from KNO₃, thus, there are 50.0g of KNO₃.

4 0

3 years ago

Cal is titrating 50.8 mL of 0.319 M HBr with 0.337 M Ba(OH)2. How many mL of Ba(OH)2 does Cal need to add to reach the equivalen

alexgriva [62]

Answer:

$V_{base}=24.04mL$

Explanation:

Hello!

In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

$2HBr+Ba(OH)_2\rightarrow BaBr_2+2H_2O$

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

$2M_{base}V_{base}=M_{acid}V_{acid}$

Therefore, for is to compute the volume of the used base, we proceed as shown below:

$V_{base}=\frac{M_{acid}V_{acid}}{2M_{base}}$

And we plug in to obtain:

$V_{base}=\frac{0.319M*50.8mL}{2*0.337M}\\\\V_{base}=24.04mL$

Best regards!

8 0

3 years ago

Gizmo Student exploration feel the heat if a solute has really strong bonds between its particles , would you expect it to form

Troyanec [42]

Answer:

The temperature of the solute/solvent without any external effect would decrease.

Explanation:

As the bonding between the solute particles is really strong, therefore a large amount of energy is required to overcome these forces. So that the new bonding between the solute and solvent is created.

In order to achieve this, there will be a lot of energy required and that is through the heating process. So the solution will require energy so the solute will dissolve fully either by provision of external force i.e stirring or by heating.

4 0

3 years ago

Round the following number to four significant figures and express the result in standard exponential notation: 442,722 *

OleMash [197]

Answer:

4.427 × 10⁵

Explanation:

In mathematics, rounding up a number is a way to get a more simpler figure but not too distant from the original number. Rounding up a whole number like this (442722) to significant figures means having only four non-zero digits in the figure i.e. 442722 ~ 442700.

This means that 442722 has been rounded up to 4s.f. Hence, to use scientific notations to represent our answer, we count the number of decimal places from right to left i.e.

442700 = 5 decimal places if the point is between 4 and 4 i.e. 4.427

Therefore, the figure 442700 can be written as 4.427 × 10⁵ using scientific notation.

5 0

3 years ago