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Levart [38]
3 years ago
5

Calculate the minimum mass of ammonia needed to produce 396 kg of ammonium sulfate, (NH4)2SO4, and excess sulfuric acid.

Chemistry
1 answer:
goldenfox [79]3 years ago
8 0

Answer:

Mass =  101891.2 g

Explanation:

Given data:

Mass of ammonia needed = ?

Mass of ammonium sulfate produced = 396 Kg = 396 ×1000 = 396000 g

Solution:

Chemical equation:

2NH₃ + H₂SO₄      →      (NH₄)₂SO₄

Number of moles of  (NH₄)₂SO₄:

Number of moles = mass/molar mass

Number of moles = 396000 g / 132.14 g/mol

Number of moles = 2996.8 mol

Now we will compare the moles of ammonia and ammonium sulfate

               (NH₄)₂SO₄          :        NH₃

                      1                   :         2

                  2996.8            :        2/1×2996.8 = 5993.6 mol

Mass of ammonia needed:

Mass = number of moles × molar mass

Mass = 5993.6 mol × 17 g/mol

Mass =  101891.2 g

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The molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

<u>Explanation:</u>

Molality is the measure of how much of amount of solute is dissolved in the solvent. So it is calculated as the ratio of moles of solute to the grams of solvent.

         \text {Molality}=\frac{\text {Moles of solute}}{\text {Mass of solvent}}

As in this case, the solute is NaCl and solvent is unknown. So the moles of solute is given as 1.34 moles and the mass of solvent is given as 2.47 kg.

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Answer:

c) 2.5 mL

Explanation:

Solution

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and

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Read 2 more answers

grin007 [14]

Answer:

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Aluminum has an atomic mass of 26.982 or 27.

The letters to unscramble are I, M, C, Al, U, and C.

The mystery element is Calcium.

Hope that helps.

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3 years ago
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