Answer:
There are 138.3 grs of Cl in CCl4 with 92.2 % of Cl in its composition.
Explanation:
You have to estimate 92.2 % of 150 grs. So,
150 grs x (92.2 %/100 %) ⇒ 138.3 grs.
Answer:
This type of meat is substance. If you were talking about meters then it would be a system of measurement.
Answer:
true
as temperatures rise, the atoms become more active; as per the opposite (meaning as temperatures drop, the atoms start to settle down) liquid is the more medium state (because the temperature rises enough for the solid to become a a liquid but not too much that the liquid evaporates and turns into a gas) have a great day/night
Answer:
A. Offspring are genetically identical to the parent.
That's the answer. I hope it helps!
The volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L
<h3>Dilution formula</h3>
M₁V₁ = M₂V₂
Where
- M₁ is the molarity of stock solution
- V₁ is the volume of stock solution
- M₂ is the molarity of diluted solution
- V₂ is the volume of diluted solution
<h3>Data obtained from the question </h3>
- Molarity of stock solution (M₁) = 24.7 mol/L
- Volume of diluted solution (V₂) = 8 L
- Molarity of diluted solution (M₂) = 10 mol/L
- Volume of stock solution needed (V₁) = ?
<h3>How to determine the volume needed </h3>
The volume of the methanol necessary to prepare the solution can be obtained as illustrated below:
M₁V₁ = M₂V₂
24.7 × V₁ = 10 × 8
24.7 × V₁= 80
Divide both side by 24.7
V₁ = 80 / 24.7
V₁ = 3.2 L
Thus, the volume of methanol necessary to prepare the antifreeze good for antifreeze solution is 3.2 L
Learn more about dilution:
brainly.com/question/15022582
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