Answer:
A mole (mol) is the amount of a substance that contains 6.02 × 10 23 representative particles of that substance. The mole is the SI unit for the amount of a substance. There are, therefore, 6.02 × 10 23 water molecules in a mole of water molecules. Water (H2O) is made from 2 atoms of hydrogen and 1 atom of oxygen.
Answer:
26.0 g/mol is the molar mass of the gas
Explanation:
We have to combine density data with the Ideal Gases Law equation to solve this:
P . V = n . R .T
Let's convert the pressure mmHg to atm by a rule of three:
760 mmHg ____ 1 atm
752 mmHg ____ (752 . 1)/760 = 0.989 atm
In density we know that 1 L, occupies 1.053 grams of gas, but we don't know the moles.
Moles = Mass / molar mass.
We can replace density data as this in the equation:
0.989 atm . 1L = (1.053 g / x ) . 0.082 L.atm/mol.K . 298K
(0.989 atm . 1L) / (0.082 L.atm/mol.K . 298K) = 1.053 g / x
0.0405 mol = 1.053 g / x
x = 1.053 g / 0.0405 mol = 26 g/mol
1 CH4 (g) + 2 O2 (g) -----> CO2 (g) + 2H2O(l) ΔH= - 890 kJ
1 mol 2 mol
1) If ΔH has minus, it means "release". We need only "release" choices.<span>
2) From reaction
1 mol </span>CH4 (g) "releases" ΔH= - 890 kJ - We do not have this choice.
2 mol O2 (g) "release" ΔH= - 890 kJ, so
1 mol O2 (g) "release" ΔH= - 445 kJ
Correct answer is B.
Answer:
The total pressure in the container is 2 atm (Option B)
Explanation:
Step 1: Data given
The initial pressure of the PCl5(g) is 1.00 atm
Volume of the container = 1.00 L
Step 2: The balanced equation
PCl5(g) ⇋ PCl3(g) + Cl2(g)
Step 3: Calculate the total pressure in the container
1mol of ideal gas has a pressure of 1 atm
If 1 mol of PCl5 completely decomposes into 1 mol PCl3 and 1 mol Cl2
Then the pressure for 1 mol PCl3 and 1 mol Cl2 is for both 1 atm
The total pressure would be 2*1 atm = 2 atm
The total pressure in the container is 2 atm
Answer:
The cell is in a Hypotonic solution. When a cell is in a Hypotonic solution the lower osmotic pressure causing water to move across the pressure gradient into the solution causing the cell to shrivel.
