This is an incomplete question, here is a complete question.
Determine which of the acids are Arrhenius acids, Brønsted–Lowry acids, and Lewis acids. It is possible for an acid to be of more than one type. Which acids are Arrhenius acids?
AlCl₃ (aq)
BCl₃ (aq)
HCl (aq)
Answer :
HCl is an Arrhenius acid and Bronsted Lowry acid
AlCl₃ is a Lewis-acid
BCl₃ is a Lewis-acid
Explanation :
According to Arrhenius concept, a base is defined as a substance which donates hydroxide ions 
when dissolved in water and an acid is defined as a substance which donates hydronium ions 
in water.
According to the Bronsted Lowry conjugate acid-base theory, an acid is defined as a substance which donates protons and a base is defined as a substance which accepts protons.
According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.
From this we conclude that:
HCl is an Arrhenius acid because it donates hydrogen ion and also Bronsted Lowry acid because it also donate protons.
AlCl₃ is a Lewis-acid because it is a electron deficient and accept lone pair of elections.
BCl₃ is a Lewis-acid because it is a electron deficient and accept lone pair of elections.
A) Mass Number
B) Protons and Electrons
C) (I think group but I'm not 100% sure on this...)
D) 12 (To work out the number of neutrons you do MASS number - ATOMIC number aka the number of protons so in this case you'd do 23-11=12)
Hope this helps
Answer:
The compound has a molar mass of 78.4 g/mol
Explanation:
Step 1: data given
Mass of a sample = 0.5 grams
Mass of benzene = 25 grams
Freezing poing = 5 °C
Kf of benzene = 5.1 °C/m
Freezing point solution = 3.7 °C
Step 2: Calculate molality
ΔT = i*Kf*m
⇒with ΔT = the freezing point depression = 5.0 - 3.7 = 1.3 °C
⇒with i = the can't hoff factor = 1
⇒with Kf = the freezing point depression constant of benzene = 5.1 °C/m
⇒with m = the molality
1.3 = 5.1 * m
m = 1.3 / 5.1
m = 0.255 moles /kg
Step 3: Calculate moles
Molality = moles / mass benzene
0.255 molal = moles / 0.025 kg
Moles = 0.255 molal * 0.025 kg
Moles = 0.006375 moles
Step 4: Calculate molar mass of the compound
Molar mass compund = mass / moles
Molar mass compound = 0.5 grams / 0.006375 moles
Molar mass compound = 78.4 g/mol
The compound has a molar mass of 78.4 g/mol
