Answer: The expression for equilibrium constant is ![\frac{[NH_3]^2}{[H_2]^3[N_2]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BH_2%5D%5E3%5BN_2%5D%7D)
Explanation: Equilibrium constant is the expression which relates the concentration of products and reactants preset at equilibrium at constant temperature. It is represented as 
For a general reaction:
The equilibrium constant is written as:
![k_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=k_c%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
Chemical reaction for the formation of ammonia is:
Expression for is:
![k_c=\frac{[NH_3]^2}{[H_2]^3[N_2]}](https://tex.z-dn.net/?f=k_c%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BH_2%5D%5E3%5BN_2%5D%7D)
![1.6\times 10^2=\frac{[NH_3]^2}{[H_2]^3[N_2]}](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E2%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BH_2%5D%5E3%5BN_2%5D%7D)
In chemistry:
The <u>molar mass</u> is the mass of a chemical element or compound divided by the amount of substance in the element.
8760 hours in a year 525600 minutes in one year 8760 times 60 equals 525600 minutes now multiply that by 5 to get <span>2628000 minutes</span>
We know,
For given reaction, 
For , 2.41 moles of 
:
We know :
Hence, this is the required solution.
Answer:
Molecular formula = C₄H₁₂O₂
Explanation:
Given data:
Percentage of hydrogen = 13.80%
Percentage of carbon = 51.02%
Percentage of oxygen = 35.18%
Molecular formula = ?
Solution:
Number of gram atoms of H = 13.80 / 1.01 = 13.6
Number of gram atoms of O = 35.18 / 16 = 2.2
Number of gram atoms of C = 51.02 / 12 = 4.25
Atomic ratio:
C : H : O
4.25/2.2 : 13.6/2.2 : 2.2/2.2
2 : 6 : 1
C : H : O = 2 : 6 : 1
Empirical formula is C₂H₆O.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = C₂H₆O = 46 g/mol
n = 88 / 46
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2 (C₂H₆O)
Molecular formula = C₄H₁₂O₂
