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kap26 [50]
3 years ago
11

What lasts longer and why?: A solar eclipse or a lunar eclipse?

Physics
1 answer:
Liono4ka [1.6K]3 years ago
5 0
Lunar eclipse can lasts longer because it lasts around 3 hours but can last as long as four hours. Solar eclipse last shorter than lunar eclipse because the moon only creates a small shadow on the earth and the moon travels through the suns vision (as seen on earth) in a short amount of time.
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What is the starting and final energy for a battery?
EleoNora [17]
Electrical energy is the starting and final energy of a battery
8 0
3 years ago
Question 4
EleoNora [17]

Answer:

D. 75 watts

Explanation:

brainliest please? i've just answered 3 of your questions and they were all correct! :) i hope i helped!

8 0
3 years ago
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Zinc metal (Zn) and sulfur powder (s) undergo a chemical reaction to form zinc sulfide (ZnS) which equation represents this chem
dexar [7]

Zinc metal (Zn) reacts with sulfur (S) to create zinc sulfide (ZnS), and the chemical reaction is: Zn (s) + S (s) = ZnS (s).

Importance of Zinc (Zn) and sulfur (S):

  • Zinc(Zn) is a vital element that our systems need to absorb food and nutrients as well as create healthy skin and bones. Zinc(Zn) ions play a crucial role in a number of the body's enzymes.
  • Sulfur(S) is a pale yellow, tasteless, brittle solid that is also necessary for life. It is found in many proteins as well as the amino acids cysteine and methionine. It is a trace element found in bone minerals, bodily fluids, and lipids.

Chemical reaction -

In this experiment, heating a zinc(Zn) and sulfur(S) combination causes an interesting chemical reaction. A blinding flash of light, hot sparks, a hissing sound, and a cloud of white smoke in the shape of a mushroom are produced.

Therefore, the following chemical processes are taking place in the reaction: Zn (s) + S (s) = ZnS (s).

Learn more about Zinc(Zn) here:

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8 0
2 years ago
If the index of refraction of a medium is 1.4, determine the speed of light in that medium.
Damm [24]

The speed of light in that medium is 2.14 \times 10^8 \ m/s.

<u>Explanation:</u>

It is known that the light's speed is constant when it travels in vacuum and the value is 3 \times 108 m/s. When the light enters another medium other than vacuum, its speed get decreased as the light gets refracted by an angle.

The amount of refraction can be determined by the index of refraction or refractive index of the medium. The refraction index is measured as the ratios of speed of light in vacuum to that in the medium. It is represented as  η = \frac {c}{v}

So, here η is the index of refraction of a medium which is given as 1.4, c is the light's speed in vacuum (3 \times 10^8 ms^-^1) and v is the light's speed in that medium which we need to find.

1.4=  \frac{(3 \times 10 ^ 8)} {v}

v=  \frac {(3 \times 10^8)}{1.4} =2.14 \times 10^8 \ m/s

Thus the speed of light in that medium is 2.14 \times 10^8 \ m/s.

3 0
3 years ago
What is the equivalent capacitance of the three capacitors in the figure (figure 1)?
vekshin1

The equivalent capacitance of the combination is  \dfrac{1}{C} = \dfrac{1}{C_1}+\dfrac{1}{C_2}  where C1 and C2 are the capacitance of both capacitors in series.

<h3>What is equivalent capacitor?</h3>

Let the capacitance of both capacitors be C1 and C2. For a series connected capacitors, same charge flows through the capacitors but different voltage flows through them.

Let Q be the amount of charge in each capacitors,

V be the voltage across each capacitors

C be the capacitance of the capacitor.

Using the formula Q = CV where V = Q/C... (1)

For the large capacitor with capacitance of the capacitor C1,

Q = C_1V_1;

V_1 = \dfrac{Q}{C_1}...(2)

where V_1 is the voltage across C_1,

For the small capacitor with capacitance of the capacitor C_2,

Q = C_2V_2;

V_2 = \dfrac{Q}{C_2} ... (3)

where V_2 is the voltage across C_2,

Total voltage V in the circuit will be;

V = V_1+V_2... (4)

Substituting equation 1, 2 and 3 in equation 4, we have;

\dfrac{Q}{C} = \dfrac{Q}{C_1} +\dfrac{ Q}{C_2}

\dfrac{Q}{C} = Q({\dfrac{1}{C_1}+\dfrac{1}{C_2})

Since change Q is the same for both capacitors since they are in series, they will cancel out to finally have;

\dfrac{1}{C} = ({\dfrac{1}{C_1}+\dfrac{1}{C_2})

This gives the equivalent capacitance of the combination.

To know more about equivalence capacitance follow

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7 0
2 years ago
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