The ultraviolet catastrophe was the prediction of late 19th century/early 20th century classical physics that an ideal black body (also blackbody) at thermal equilibrium will emit radiation in all frequency ranges, emitting more energy as the frequency increases.
Answer:
605 km
Explanation:
Hello
the same units of measure should be used, then
Step 1
convert 42 m/s ⇒ km/h
1 km =1000 m
1 h = 36000 sec
![42 \frac{m}{s}*\frac{1\ km}{1000\ m}=0.042\ \frac{km}{s}\\ 0.042\ \frac{km}{s}\\](https://tex.z-dn.net/?f=42%20%5Cfrac%7Bm%7D%7Bs%7D%2A%5Cfrac%7B1%5C%20km%7D%7B1000%5C%20m%7D%3D0.042%5C%20%5Cfrac%7Bkm%7D%7Bs%7D%5C%5C%200.042%5C%20%5Cfrac%7Bkm%7D%7Bs%7D%5C%5C)
![0.042\ \frac{km}{s}*\frac{3600\ s}{1\ h} =151.2 \frac{km}{h}\\ \\Velocity =151.2\ \frac{km}{h}](https://tex.z-dn.net/?f=0.042%5C%20%5Cfrac%7Bkm%7D%7Bs%7D%2A%5Cfrac%7B3600%5C%20s%7D%7B1%5C%20h%7D%20%3D151.2%20%5Cfrac%7Bkm%7D%7Bh%7D%5C%5C%20%5C%5CVelocity%20%3D151.2%5C%20%5Cfrac%7Bkm%7D%7Bh%7D)
Step 2
find kilometers traveled after 4 hours
![V=\frac{s}{t}\\ \\](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Bs%7D%7Bt%7D%5C%5C%20%5C%5C)
V,velocity
s, distance traveled
t. time
now, isolating s
![V=\frac{s}{t} \\s=V * t\\](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Bs%7D%7Bt%7D%20%5C%5Cs%3DV%20%2A%20t%5C%5C)
and replacing
![s=V * t\\s=151.2\frac{km}{h}*4 hours\\ s=604.8 km\\](https://tex.z-dn.net/?f=s%3DV%20%2A%20t%5C%5Cs%3D151.2%5Cfrac%7Bkm%7D%7Bh%7D%2A4%20hours%5C%5C%20s%3D604.8%20km%5C%5C)
S=604.8 Km
Have a great day
Answer:
Potential energy of book = 7.5 J
Explanation:
Given:
Weight of book = 5 N
Height of shelf = 1.5 meter
Find:
Potential energy of book
Computation:
Weight = Mass x Acceleration of gravity
Mass x Acceleration of gravity = 5 N
Potential energy = Mass x Acceleration of gravity x Height
Potential energy of book = Mass x Acceleration of gravity x Height
We know that;
Mass x Acceleration of gravity = 5 N
So,
Potential energy of book = 5 x 1.5
Potential energy of book = 7.5 J
-- Class I lever
The fulcrum is between the effort and the load.
The Mechanical Advantage can be anything, more or less than 1 .
Example: a see-saw
-- Class II lever
The load is between the fulcrum and the effort.
The Mechanical Advantage is always greater than 1 .
Example: a nut-cracker, a garlic press
-- Class III lever
The effort is between the fulcrum and the load.
The Mechanical Advantage is always less than 1 .
I can't think of an example right now.
Answer:
v=115 m/s
or
v=414 km/h
Explanation:
Given data
![A_{area}=0.140m^{2}\\ p_{air}=1.21 kg/m^{3}\\ m_{mass}=80kg](https://tex.z-dn.net/?f=A_%7Barea%7D%3D0.140m%5E%7B2%7D%5C%5C%20%20p_%7Bair%7D%3D1.21%20kg%2Fm%5E%7B3%7D%5C%5C%20%20m_%7Bmass%7D%3D80kg)
To find
Terminal velocity (in meters per second and kilometers per hour)
Solution
At terminal speed the weight equal the drag force
![mg=1/2*C*p_{air}*v^{2}*A_{area}\\ v=\sqrt{\frac{2*m*g}{C**p_{air}*A_{area}} }\\ Where C=0.7\\v=\sqrt{\frac{2*9.8*80}{1.21*0.14*0.7} }\\ v=115m/s](https://tex.z-dn.net/?f=mg%3D1%2F2%2AC%2Ap_%7Bair%7D%2Av%5E%7B2%7D%2AA_%7Barea%7D%5C%5C%20%20%20v%3D%5Csqrt%7B%5Cfrac%7B2%2Am%2Ag%7D%7BC%2A%2Ap_%7Bair%7D%2AA_%7Barea%7D%7D%20%7D%5C%5C%20Where%20C%3D0.7%5C%5Cv%3D%5Csqrt%7B%5Cfrac%7B2%2A9.8%2A80%7D%7B1.21%2A0.14%2A0.7%7D%20%7D%5C%5C%20v%3D115m%2Fs)
For speed in km/h(kilometers per hour)
To convert m/s to km/h you need to multiply the speed value by 3.6