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andrew-mc [135]
3 years ago
14

A small, positively charged ball is moved close to a large, positively charged ball. Which describes how the small ball likely r

esponds when it is released?
It will move toward the large ball because like charges repel.
It will move toward the large ball because like charges attract.
It will move away from the large ball because like charges repel.
It will move away from the large ball because like charges attract.
Physics
2 answers:
Angelina_Jolie [31]3 years ago
8 0

Answer:c

Explanation:

Ludmilka [50]3 years ago
7 0

Answer:

C

Explanation:

i took the test

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Explanation:

The electric potential is the electric potential energy per unit of charge

V=\frac{U}{q}

Using this definition, we can calculate the electrostatic potential energy change between point A and B:

\Delta U=U_A-U_B\\\Delta U=qV_A-qV_B\\\Delta U=q(V_A-V_B)

Electron: q=-1.6*10^{-19}C

\Delta U=-1.6*10^{-19}C(11.3V+25.9V)\\\Delta U=-5.952*10^{-18}J

Proton: q=1.6*10^{-19}C

\Delta U=1.6*10^{-19}C(11.3V+25.9V)\\\Delta U=5.952*10^{-18}J

Neutral hydrogen atom: q=0

\Delta U=0

Singly ionized helium atom: q=1.6*10^{-19}C

\Delta U=1.6*10^{-19}C(11.3V+25.9V)\\\Delta U=5.952*10^{-18}J

8 0
3 years ago
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2 years ago
Refrigerant-134a enters the expansion valve of a refrigeration system at 160 psia as a saturated liquid and leaves at 30 psia. D
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Answer:

Temperature : 92.9 F

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Explanation:

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mh1=mh2

h1=h2

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u1=41.49

So T1=90.49 F

P2=20Psi

h2=h1= 41.79 Btu/lbm

T2= -2.43F

u2= 38.96 Btu/lbm

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6 0
3 years ago
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Arturiano [62]

Answer:

W = 285.62 N

Explanation:

It is given that,

Mass of Jessica is 55 kg

Slope of the hill is 32 degrees

We need to find the component of her weight that is along her direction of motion.

The component along her direction of motion is shown in attached figure. It means

W_y=mg\sin\theta\\\\W_y=55\times 9.8\times \sin(32)\\\\W_y=285.62\ N

So, the component of her weight that is along her direction of motion is 285.62 N.

7 0
3 years ago
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