Answer:
his acceleration rate is -0.00186 m/s²
Explanation:
Given;
initial position of the car, x₀ = 100 miles = 160, 900 m ( 1 mile = 1609 m)
time of motion, t₀ = 60 minutes = 60 mins x 60 s = 3,600 s
final position of the car, x₁ = 150 miles = 241,350 m
time of motion, t₁ = 100 minutes = 100 mins x 60 s = 6,000 s
The initial velocity is calculated as;
u = 160, 900 m / 3,600 s
u = 44.694 m/s
The final velocity is calculated as;
v = 241,350 m / 6,000 s
v = 40.225 m/s
The acceleration is calculated as;
Therefore, his acceleration rate is -0.00186 m/s²
Work done by the car is 3900 J
Explanation:
- Power and work are related by the equation, Power = Work Done/Time
- Power is the rate at which work is done.
- Here, the car uses power of 260 W and time taken is 15 s.
Work Done = Power × Time
= 260 × 15 = 3900 J
Energy is the capacity to do work. Energy exists in various forms in the entire universe.
It may be light,sound,electric,magnetic,kinetic,potential,thermal energy etc.
As per the law of conservation of energy, it is neither created not destroyed. It can change from one form to another form.The total energy of the universe is always constant.
The process in which energy will change from one form to another form is called energy conversion.
There is also another terminology for energy conversion called energy transformation.
Energy transference is the process in which energy will be transferred from one body to another body.
Hence the correct answer to this question will be conversion and transformation
Answer:
The resistance must be 6.67
Solution:
Resistance, 
Resistance, 
For the current to be the same when the switch is open or closed, the resistances must be connected in parallel as current is distributed in parallel with the same voltage across the circuit:
Thus in parallel:
Answer:
The reason is because both are exposed to a virtually infinite heat sink, due to the virtually infinite mass and of the surrounding environment, compared to the sizes of either the cup or the kettle such that the equilibrium temperature, 
reached is the same for both the cup and the kettle as given by the relation;
Due to the large heat sink, T₂ - T₁ ≈ 0 such that the temperature of the kettle and that of the cup will both cool to the temperature of the environment
Explanation:
