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3 years ago

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two charges having the same charge magnitude experiencing an attracting force of 3.60N when the charges are 30cm apart.what is t

he charge magnitude in micro coulombs and the sign of each charge? Q1= q2=

1 answer:

Tomtit [17]3 years ago

3 0

The charges have opposite sign and magnitude $6 \mu C$

Explanation:

The magnitude of the electrostatic force between two electric charges is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

In this problem, we have:

F = 3.60 N is the force between the two charges

r = 30 cm = 0.30 m is their separation

The two charges have same magnitude, so

$q_1 = q_2 = q$

So we can rewrite the equation as

$F=\frac{kq^2}{r^2}$

And solving for q:

$q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(3.60)(0.30)^2}{8.99\cdot 10^9}}=6\cdot 10^{-6} C = 6\mu C$

Moreover, the force between the charges is attractive: we know that charges of same sign repel each other while charges of opposite sign attract each other, therefore the charges in this problem have opposite sign, so

$q_1 = 6 \mu C\\q_2 = -6 \mu C$

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

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A ball is thrown vertically upward with an initial velocity of 23.6 meters per second. What is the maximum height reached by the

REY [17]

Answer:

Maximum height attained by the ball will be h = 28.416 m

Explanation:

We have given initial speed of the ball u = 23.6 m /sec

At maximum height velocity will be zero so final velocity v = 0 m/sec

Acceleration due to gravity $g=9.8m/sec^2$

From law of motion we know that $v^2=u^2-2gh$

$0^2=23.6^2-2\times 9.8\times h$

h = 28.416 m

So maximum height attained by the ball will be h = 28.416 m

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3 years ago

Earth orbits once around the sun every 365.25 days at an average radius of 1.5X10^11 m. Earth's mass is 6X10^24 kg. What distanc

Katyanochek1 [597]

(a) The distance the Earth travels every year is the perimeter of the orbit; since we have the average radius of the orbit, we can calculate the perimeter:
$d=2\pi r = 2 \pi (1.5 \cdot 10^{11}m)=9.4 \cdot 10^{11}m$

(b) The average centripetal acceleration is given by
$a_c = \frac{v^2}{r}$
where v is the average speed of the Earth, that we can find by dividing the distance covered by the Earth in one year (=the perimeter of the orbit) by the the time corresponding to 1 year:
t=1 year=365.25 days=3.2 \cdot 10^7 s
So the velocity is:
$v= \frac{d}{t}= \frac{9.4 \cdot 10^{11}m}{3.2 \cdot 10^7 s} =2.94 \cdot 10^4 m/s$
And so the centripetal acceleration is:
$a_c = \frac{v^2}{r}= \frac{(2.94 \cdot 10^4 m/s)^2}{9.4 \cdot 10^{11}m} =9.2 \cdot 10^{-4} m/s^2$

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3 years ago

Suppose you stand with one foot on ceramic flooring and one on a wool carpet, making contact over a 77.2 cm2 area with each foot

Finger [1]

Answer:

$P_{c$ = 5.74W

$P_{w}$ =0.27 W

Explanation:

d= 2.6cm =>0.026m (for both the ceramic and the carpet )

Thermal conductivity of wool ' $k_{w}$ '= $k_{carpet}$ = $k_{wool}$ = 0.04J/(sm °C)

Thermal conducticity of carpet ' $k_c}$ ' = 0.84 J/(sm °C)

Area 'A'= $A_{carpet}$ = $A_{ceramic}$ = 77.2cm²=> 77.2 x $10^{-4}$ m²

$T_h}$ =33.0°C

$T_c}$ =10.0°C

Average Power $P_{avg}$ is determined by dividing amount of energy'Q' by time taken for the transfer't':

$P_{avg}$ = Q/Δt

Due to conductivity, heat of flow rate will be P= dQ/dt

P= $\frac{dQ}{dt}$ = $\frac{kA[T_{h}-T_{c} ]}{d}$

For CERAMIC:

$P_{c$ = $\frac{k_{c} A[T_{h}-T_{c} ]}{d}$ => [0.84 x 77.2 x $10^{-4}$ (33-10) ]/0.026

$P_{c$ = 5.74W

For WOOL CARPET:

$P_{w}$ = $\frac{k_{w} A[T_{h}-T_{c} ]}{d}$ => [0.04 x 77.2 x $10^{-4}$ (33-10) ]/0.026

$P_{w}$ =0.27 W

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3 years ago

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Zigmanuir [339]

Difference Between a Scalar & Vector Quantity:

A vector quantity has a direction and a magnitude, while a scalar quantity only has magnitude.

Examples:

Scalar quantity include things like speed, time, volume, mass and temperature, while Vector quantities include things like acceleration, velocity, force, momentum and the increase and decrease in temperature.

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