Carlita was either sipping the hot chocolate while she was out, or else
approximating the numbers. The exact number she reported is not
possible. To see why, I'll do it strictly by the math:
Robins = 5 times
Cardinals = 1 time
Total birds = 6 times
6 times = 25 birds
Divide each side by 6 : 1 time = 25/6 = 4-1/6 birds
Robins = 5 times = 20-5/6 of them
Cardinals = 1 time = 4-1/6 of them
Total: (20-5/6) + (4-1/6) = 25 birds.
How many more robins than cardinals = (20-5/6) - (4-1/6) = 16-2/3 more.
The math works out fine. But if the numbers she reported are true,
then some of what she saw was partial birds ... legs, or feathers,
things like that. Eeeew. I don't want to talk about it.
Answer:
4104.79 Seconds or about 1.14 Hours
Step-by-step explanation:
26mi = 41842.9m
100/9.81 = 41842.9/x
41842.9 x 9.81 = 100x
410478.849 = 100x
x = 4104.78849
The answer is 3/6.
So we know that 2/4 is equivalent to 1/2. 1/2 of 6 is 3. We can make this our numerator and our denominator as 6.
Answer:
Yes, result is significant ; PVALUE < α
Step-by-step explanation:
Given :
x = 536
n = sample size = 1012
Phat = x / n = 536 / 1012 = 0.5296 = 0.53
H0 : P0 = 0.5
H1 : P0 > 0.5
Test statistic :
(Phat - P0) ÷ sqrt[(P0(1 - P0)) / n]
1-P0 = 1 - 0.5 = 0.5
(0.53 - 0.5) ÷ sqrt[(0.5*0.5)/1012]
0.03 ÷ 0.0157173
= 1.9087
Pvalue :
Using the Pvalue from test statistic :
Pvalue = 0.02815
To test if result is significant :
α = 0.05
0.02815 < 0.05
Pvalue < α ; Hence, result is significant at α=0.05; Hence, we reject H0.
