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andreyandreev [35.5K]
3 years ago
7

Jeff has $24. He spend $10.81, including tax, to buy a new DVD. He needs to set aside $10 to pay for his lunch next week. If pea

nuts cost $0.38 per package, including tax, what is the maximum number of packages Jeff can buy???? Plzzz I will give you 100 points
Mathematics
1 answer:
nata0808 [166]3 years ago
8 0

Answer:

He can buy 8 packages of peanuts

Step-by-step explanation:

24 - 10.81 = 13.19   Subtract the DVD cost from the $24

13.19 - 10 Subtract the amount that he needs to set aside

3.19 / 0.38 Divide

8 Round to the nearest whole package

8 packages


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What is the missing divisor 18.3 ÷ ____ = 3.05
777dan777 [17]

Answer:

6

Step-by-step explanation:

18.3/3.05=6

18.3 / 6=3.05

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a baseball team played 35 games and won 4/7 of them. How many games were won? How many games were lost?
nikklg [1K]
Won: 4/7 x 35 = 20
lost: 3/7 x 35 = 15
6 0
3 years ago
One person wants to get a 95% z-confidence interval with a margin of error of at most 15 based on a population standard deviatio
Bess [88]

Answer:

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=60 represent the population standard deviation  

n represent the sample size (variable of interest)  

Confidence =95% or 0.95

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =15, and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

6 0
3 years ago
Simplify x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2
Artemon [7]

Answer:

2x^2 + 2y^2 + 2z^2

Step-by-step explanation:

x^2+xy-yx+y^2 + y^2+yz-zy+z^2 + z^2+zx-xz+x^2

First step is to put all the same ones together

( FYI, xy and yx is the same thing, just like how

2 x 3 and 3 x 2 is the same thing) this time I'll bracket the groups to make it easier on the eyes

(x^2 +x^2) + (xy - xy) +( y^2 + y^2) + (yz - yz) +

(z^2 +z^2) + (zx - zx)

2x^2 + 2y^2 + 2z^2

All the others just cancel themselves out, for example, xy-xy

When anything minus themselves it will become 0

7 0
3 years ago
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