Sorry I’m only answering this so I can ask
Starting off, we can multiply the third equation by 2 and add it to the third to get rid of both the x and y variables. Next, we get z=1. Plugging that into 3y-5z=-23, we get 3y-5=-23. Adding 5 to both sides, we get 3y=-18. After that, we can divide both sides by 3 to get y=-6. Plugging that into -2x-y-z=-3, we get -2x+6-1=-3=-2x+5. Subtracting 5x from both sides, we get -2x=-8. After that, we can divide both sides by -2 to get x=4.
If this is regards to science and take off then <span>V1= Takeoff decision speed.
VR= Rotation speed. V2=Single engine climb speed. .</span>
Let
x = 3a (first angle)
y = 3a (second angle)
z = 6a (third angle)
The total angle of a triangle is ALWAYS 180.
3a + 3a + 6a = 180
12a = 180
a = 15
Therefore, x = 45, y = 45, z = 90
The angle x is half the sum of the intercepted arcs, PQ and NO.
... (1/2)(65° + 45°) = 55° = x° = m∠PMQ
