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3 years ago

Help me pleaseeeeeeeeeeeeeee

Mathematics

2 answers:

IgorC [24]3 years ago

3 0

It's the second one but I'm. Not sure that's a right triangle so where the c is just figure the number of c

Mice21 [21]3 years ago

3 0

Hypotenuse is the longest side of the triangle. Sooo. If you use process of elimination you should get B. Because 5 too short. 10 too short. 625 waaaay too long. So 17.8 should be correct.

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Describe and correct the error in writing an equation of the line shown

Rudiy27

Answer:

$y = -\frac{3}{5}x+4$

Step-by-step explanation:

Given:

$(x_1,y_1) = (0,4)$

$(x_2,y_2) = (5,1)$

The attachment completes the question

From the attachment, the slope of the line was calculated as:

$m = \frac{1-4}{0-5}$

This step is inaccurate because the slope of a line is calculated using

$m = \frac{y_2-y_1}{x_2-x_1}$

Which gives

$m = \frac{1-4}{5-0}$

$m = \frac{-3}{5}$

$m = -\frac{3}{5}$

The line equation is then calculated using:

$y -y_1 = m(x - x_1)$

Substitute values for m, x1 and y1

$y - 4 = -\frac{3}{5}(x - 0)$

$y - 4 = -\frac{3}{5}(x)$

Open bracket

$y - 4 = -\frac{3}{5}x$

Make y the subject

$y = -\frac{3}{5}x+4$

6 0

2 years ago

Simplify 2√2-√3<br> ---------------<br> √2+√3

serious [3.7K]

Step-by-step explanation:

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} }$

$= \frac{2 \sqrt{2} - \sqrt{3} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} }$

$= \frac{ 2( \sqrt{2} - \sqrt{3} )( \sqrt{2} - \sqrt{3} )}{ { \sqrt{2} }^{2} - { \sqrt{3} }^{2} }$

$= \frac{2(2 - \sqrt{6} - \sqrt{6} - 3) }{2 - 3}$

$= \frac{2( - 1 - 2 \sqrt{6} )}{ - 1}$

$= \frac{ - 2(1 + 2 \sqrt{6} )}{ - 1}$

$= 2(1 + 2 \sqrt{6} )$

$= 2 + 4 \sqrt{6}$

6 0

1 year ago

Need Help!

Contact [7]

Answer:

4) Alternate Interior angles 5) Parallel lines property.

Step-by-step explanation:

The question is asking us to Complete the statements to prove that line AB ⩭ to line CD and line BC ⩭ to line AD.

In statement 4 .∠CAB is congruent to ∠ACD as AB is parallel to CD and ∠BCA is congruent to∠CAD as AD is parallel to BC and these are Alternate interior angles to the parallel lines .

In statement 5.m∠CAB =∠ACD and ∠BCA = ∠CAD as by property of parallel lines Alternate interior angles are equal.

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Answer:

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