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mihalych1998 [28]
4 years ago
10

By mistake, you added salt instead of sugar to the oil. How can you remove the salt?

Chemistry
2 answers:
Hitman42 [59]4 years ago
6 0

Answer:

Salt is ionic, and oil is covalent. If you add water, the salt will dissolve in the water, and the oil will float to the top. You could then skim the oil and start over with sugar. To double-check, you could even make sure the oil does not conduct electricity!

Explanation:

just took on edge 2020

Ghella [55]4 years ago
5 0

Explanation:

To remove the salt from the oil, I will add water to dissolve the salt from it.

Oil is an organic molecule that is non-polar

Salt is polar ionic compound

Salt will not dissolve in the oil.

  • Take the mixture.
  • Add water to it.
  • Water and oil are immiscible
  • Shake the new heterogeneous mixture vigorously.
  • leave to settle.
  • Oil will come on top of the water.
  • You can skim off the oil layer on top.
  • Then heat the water and salt solution.
  • This leaves the oil behind.

learn more:

Mixture brainly.com/question/1832352

#learnwithBrainly

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1) The order of the reaction is of FIRST ORDER

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From the given information:

The composition of a liquid-phase reaction 2A - B was monitored spectrophotometrically.

liquid-phase reaction 2A - B signifies that the reaction is of FIRST ORDER where the rate of this reaction is directly proportional to the concentration of A.

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To start with the value of t when t = 10 mins

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 - 0}{0.312 - 0.089})

K_1 = \dfrac{1}{10} \ In ( \dfrac{0.312 }{0.223})

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K_2= \dfrac{1}{20} \ In ( \dfrac{0.312 - 0}{0.312 - 0.153})

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When t = 30

K_3= \dfrac{1}{30} \ In ( \dfrac{0.312 - 0}{0.312 - 0.200})

K_3= 0.0333 \times  \ In ( \dfrac{0.312}{0.112})

K_3= 0.0333 \times  \ 1.0245

K_3 = 0.03412 \ min^{-1}

K_3 = 0.034 \ min^{-1}

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K_4= \dfrac{1}{40} \ In ( \dfrac{0.312 - 0}{0.312 - 0.230})

K_4=0.025 \times  \ In ( \dfrac{0.312}{0.082})

K_4=0.025 \times  \ In ( 3.8048)

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We can see that at the different time rates, the rate constant of k_1, k_2, k_3, and k_4 all have similar constant values

As such :

Rate constant k = 0.034 min⁻¹

Converting it to seconds ; we have :

60 seconds = 1 min

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0.034 min⁻¹ =(0.034/60) seconds

= 5.667 × 10 ⁻⁴ seconds

Rate constant k = 5.667 × 10 ⁻⁴

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