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anyanavicka [17]
3 years ago
6

How can the rate of a reaction be increased?

Chemistry
1 answer:
Nesterboy [21]3 years ago
6 0

Explanation:

Rate of reaction can be increased by having more surface area.

Therefore,

Option B is correct✔

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Which of the following elements will produce the same spectrum?
Bond [772]
We are given with the following pairs:
<span>carbon and oxygen
hydrogen and helium
gold and silver
and we are asked if there is a pair that will produce the same spectrum. The answer is
</span>No two elements produce the same spectrum.This is because a light spectrum is unique to each element.
3 0
3 years ago
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did this and got 8.3 x 10-5 can someone help me figure out how i got this wrong since these are the only answer choices?
Bezzdna [24]
It is b i think bc it looks like it would be it and my tudor helped me
4 0
2 years ago
Which of the following is a mixture of substances?
Stels [109]

Answer:

the answer is c

b/c contain more than one element

7 0
3 years ago
A closed system initially containing 1×10^-3 hydrogen 2×10^-3M iodine at 448 degree Celsius and is allowed to reach equilibrium.
GaryK [48]

Answer:

Kc = 50.5

Explanation:

We determine the reaction:

H₂  +  I₂   ⇄   2HI

Initially we have 0.001 molesof H₂

and 0.002 moles of I₂

If we have produced 0.00187 moles of HI in the equilibrium we have to know, how many moles of I₂ and H₂, have reacted.

           H₂     +      I₂      ⇄   2HI

In:     0.001       0.002           -

R:       x                 x                2x

Eq:  0.001-x    0.002-x      0.00187  

x = 0.00187/2 = 9.35×10⁻⁴ moles that have reacted

So in the equilibrium we have:

0.001 - 9.35×10⁻⁴ = 6.5×10⁻⁵  moles of H₂

0.002 - 9.35×10⁻⁴ = 1.065×10⁻³ moles of I₂

Expression for Kc is =  (HI)² / (H₂) . (I₂)

0.00187 ² /  6.5×10⁻⁵ . 1.065×10⁻³ = 50.5

5 0
3 years ago
Ethanol has a Kb of 1.22 Degrees C/m and usually boils at 78.4 Degrees Celcius. How many mol of an nonionizing solute would need
Gala2k [10]

Answer:

0.3097 moles of an nonionizing solute would need to be added.

Explanation:

Molal elevation constant = k_b=1.22^oC/m

Normal boiling point of ethanol = T_o=78.4^oC

Boiling of solution =T_b=86.30^oC

Moles of nonionizing solute = n

Mass of ethanol (solvent) = 47.84 g

Elevation boiling point:

\Delta T_b=T_b-T_o

\Delta T_b=86.30^oC-78.4^oC=7.9^oC

\Delta T_b=K_b\times  m

m=\frac{\text{Moloes of solute}}{\text{Mass of solvent(kg)}}

7.9^oC=1.22^oC/m\times \frac{n}{0.04784 kg}

n = 0.3097 mol

0.3097 moles of an nonionizing solute would need to be added.

4 0
3 years ago
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