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3 years ago

What is the length of the TV if it is 45.25 inches wide and 24.5 inches tall ?

Mathematics

1 answer:

Vsevolod [243]3 years ago

5 0

You are asking for length,

There is area, width, and length.

There is no area/square feet or any hints of area.

We already have wide for width

So that makes the 24.5 inches tall the length

the answer is 24.5 inches

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Find <img src="https://tex.z-dn.net/?f=a_%7B1%7D" id="TexFormula1" title="a_{1}" alt="a_{1}" align="absmiddle" class="latex-form

yKpoI14uk [10]

Answer:

$\displaystyle a_{1} = 108$

Step-by-step explanation:

we are given

the sum,common difference and nth term of a geometric sequence

we want to figure out the first term

recall geometric sequence

$\displaystyle S_{ \text{n}} = \frac{ a_{1}(1 - {r}^{n} )}{1 - r}$

we are given that

$S_n=189$
$r=\dfrac{1}{2}$
$n=3$

thus substitute:

$\displaystyle 189= \frac{ a_{1}(1 - {( \frac{1}{2} )}^{3} )}{1 - \frac{1}{2} }$

to figure out $a_1$ we need to figure out the equation

simplify denominator:

$\displaystyle \frac{ a_{1}(1 - {( \frac{1}{2} )}^{3} )}{ \dfrac{1}{2} } = 189$

simplify square:

$\displaystyle \frac{ a_{1}(1 - {( \frac{1}{8} )}^{} )}{ \dfrac{1}{2} } = 189$

simplify substraction:

$\displaystyle \frac{ a_{1} (\frac{7}{8} )}{ \frac{1}{2} } = 189$

simplify complex fraction:

$\displaystyle a_{1} (\frac{7}{8} ) \div { \frac{1}{2} } = 189$

calculate reciprocal:

$\displaystyle a_{1} \frac{7}{8} \times 2 = 189$

reduce fraction:

$\displaystyle a_{1} \frac{7}{4} \ = 189$

multiply both sides by 4/7:

$\displaystyle a_{1} \frac{7}{4} \times \frac{4}{7} \ = 189 \times \frac{4}{7}$

reduce fraction:

$\displaystyle a_{1} = 27\times 4$

simplify multiplication:

$\displaystyle a_{1} = 108$

hence,

$\displaystyle a_{1} = 108$

4 0

3 years ago

Solve equation for y: -4x+8y=24

Nesterboy [21]

-4x +8y = 24

8y = 24+ 4x
y = 24/8 + 4x/8
y = 3+ x/2

Hope it helps!
#MissionExam001

4 0

3 years ago

Out of a sample 650 high school students, 321 take the bus to school every day. construct a 99% confidence interval for the popu

gtnhenbr [62]

A 99% confidence interval for the population mean of high school students that take the bus to school every day is b) ci=(44.34%, 54.43%)

We need to find the 99% confidence interval for the population mean of high school students that take the bus to school everyday

A confidence interval is a range of estimates for an unknown parameter. The confidence interval is calculated at the specified confidence level; the most common is the 95% confidence level, but sometimes other levels are used, such as 90% or 99%.

The confidence interval of proportions is given by:

π ± z √(π (1-π) /n)

π is the sample proportion.

z is the critical value.

n is the sample size.

For 99% confidence interval the value of z is 2.58

π = 321/650

The confidence interval is given by

=321/650 ± 2.58 √( (321/650) × [ 1 - (321/650) ] ÷ 650)

= (0.493846 ± 0.050594)

=(0.4434 , 0.5443)

=(44.34 % , 54.43 %)