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Sonja [21]
3 years ago
11

100d=13.71 d is what

Mathematics
1 answer:
kherson [118]3 years ago
5 0

Answer:

261661bdhejejejejejdjbene Y qllwlqqlo2o1001100

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Solve the equation by putting it in factored form and using the Zero Product Property: x2 + 12x +11 = 0
nekit [7.7K]

Answer:

janarver 12- mae verdemax x-

Step-by-step explanation:

5 0
2 years ago
You have to download question
solmaris [256]

Answer:

B) Mode doesn't change.

Step-by-step explanation:

Given:

A set of data with 16 being added to the set.

The mode of a given set of data is the data that is repeated the most number of times.

Here, 19 is repeated 3 times, so the mode is 19.

Now, if a number other than that of 19 being added, doesn't affect the mode of the data set as 19 will still be 3 times and adding 16 will not increase its number in the set.

So, the correct option is B.

4 0
3 years ago
One bar of candy A and two bars of candy B have 774 calories. Two bars of candy A and one bar of candy B contains 786 calories.
vampirchik [111]
◆ Define the variables:

Let the calorie content of Candy A = a
and the calorie content of Candy B = b

◆ Form the equations:

One bar of candy A and two bars of candy B have 774 calories. Thus:

a + 2b = 774

Two bars of candy A and one bar of candy B contains 786 calories

2a + b = 786

◆ Solve the equations:

From first equation,
a + 2b = 774
=> a = 774 - 2b

Put a in second equation
2×(774-2b) + b = 786
=> 2×774 - 2×2b + b = 786
=> 1548 - 4b + b = 786
=> -3b = 786 - 1548
=> -3b = -762
=> b = -762/(-3) = 254 calorie

◆ Find caloric content:

Caloric content of candy B = 254 calorie

Caloric content of candy A = a = 774 - 2b = 774 - 2×254 = 774 - 508 = 266 calorie
5 0
3 years ago
Find the mean of 1,0,10,7,13,2,9,15,0,3
svet-max [94.6K]
1,0,10,7,13,2,9,15,0,3/ 10
=60/10
=6
8 0
3 years ago
Read 2 more answers
108÷9⋅(−12)÷6−(100÷5)
pochemuha

Answer:

-44

Step-by-step explanation:

5 0
3 years ago
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