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Sonja [21]
3 years ago
11

100d=13.71 d is what

Mathematics
1 answer:
kherson [118]3 years ago
5 0

Answer:

261661bdhejejejejejdjbene Y qllwlqqlo2o1001100

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Plz Help.......
lana66690 [7]

Answer:

For product A, the product is increasing, for the bigger the number you plug into x (due to the fact that the numbers become bigger because of the time: year 1, year 2, etc)

Product A is 82% change rate, while

product B is 983.45/4 = 245.8625,  1756.16/3 = 585.3867

Product B is 245.8625/585.3867

product B is 42% change rate

Product A change rate is higher than Product B by 40%

Step-by-step explanation:

Hope this helped! :)

6 0
3 years ago
PLS HELP IM TIMED!!
yanalaym [24]

Answer:

A) 150°

Step-by-step explanation:

Hope I helped you

3 0
3 years ago
Read 2 more answers
What is the following product?
-Dominant- [34]

Answer:

98 - 40√6

Step-by-step explanation:

We have to simplify the following product :

(5\sqrt{2} - 4\sqrt{3})(5\sqrt{2} - 4\sqrt{3}).

Now, (5\sqrt{2} - 4\sqrt{3})(5\sqrt{2} - 4\sqrt{3})

= (5\sqrt{2} - 4\sqrt{3})^{2}

= (5\sqrt{2})^{2} - 2 (5\sqrt{2}) (4\sqrt{3}) + (4\sqrt{3} )^{2}  

{Since we know the identity (a - b)² = a² - 2ab + b² }

= 50 - 40√6 + 48

= 98 - 40√6 (Answer)

6 0
3 years ago
Read 2 more answers
The area of a playground is 336 yd2. The width of the playground is 5 yd longer than its length. Find the length and width of th
kondaur [170]
L=16
W=21

Set up a systems of equations: 
x=length 
y=width 

xy=336
x+5=y

Use substitution to solve: 
x(x+5)=336
x^2+5x=336 

Solve using factoring: 
x^2+5x-336=0
(x-16)(x+21)=0
x=16 and x= -21 
Since length can't be negative, l=16 

To find width, plug length into the first equation: 
(16)y=336
y=21 

So...
L=16
<span>W=21</span>
7 0
3 years ago
Read 2 more answers
X^2=4x-15 solve with Quadratic formula
bulgar [2K]

Answer:

x=2+i\sqrt{11}

x=2-i\sqrt{11}

Step-by-step explanation:

we have

x^{2} =4x-15 -------> x^{2}-4x+15=0

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^{2}-4x+15=0

so

a=1\\b=-4\\c=15

substitute in the formula

x=\frac{-(-4)(+/-)\sqrt{-4^{2}-4(1)(15)}} {2(1)}

x=\frac{4(+/-)\sqrt{16-60}} {2}

Remember that

i=\sqrt{-1}

x=\frac{4(+/-)\sqrt{-44}} {2}

x=\frac{4(+/-)2i\sqrt{11}} {2}

x=\frac{4(+)2i\sqrt{11}}{2}=2+i\sqrt{11}

x=\frac{4(-)2i\sqrt{11}}{2}=2-i\sqrt{11}

7 0
3 years ago
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