Answer:
D) The baby will continue to move forward as the car slows and be push into the padded car seat.
Explanation:
Newton's first law states that an object tends to be in a state of rest or motion unless and until an unbalanced external force acts on it. This means a body would continue to be in a state of motion unless external force stops it. A body in the state of rest will remain at rest unless an external force moves it.
An infant car seat is made to face the rear of the car. This is because, in case of a front-end collision, the car would come to a sudden stop but the bodies inside the car are in a state of motion and a sudden halt will cause the body to push in the opposite direction.
Thus, for an infant in the car, it would be a safer measure to place the seat facing the rear o the car because in this case, it would cause the baby to safely collide with the padded seat of the car.
In a number with decimal, zeroes to the right of last non-zero digit are significant.
Hence there are 4 significant digits in 3.140.
Hope this helps, have a great day ahead!
Molar mass NaOH =23+16+1=40 g/mol
<span> 0.100 M= 0.100 mol/L
</span>500 ml=0.500 L
0.500L*0.100 mol/L=0.0500 mol NaOH we need to prepare 500 ml solution
0.0500 mol NaOH*40g/1mol=2 g NaOH we need to prepare 500 ml solution
we need 2 g NaOH, dissolve it in small amount of water, and dilute it with water up to 500 mL
Because in difrent materials atoms are more compact or less compact.if they are less compact then it will be easear for them to move
If a gas in a balloon occupies 2.25 L at 298 K and 300 kPa, the temperature at which the balloon expand to 3.50L and 2.17 atm is 345.23K.
<h3>How to calculate temperature?</h3>
The temperature of an ideal gas can be calculated using the following formula:
P1V1/T1 = P2V2/T2
Where;
- P1 = initial pressure
- P2 = final pressure
- V1 = initial volume
- V2 = final volume
- T1 = initial temperature
- T2 = final temperature
According to the information given in this question;
- P1 = 300kpa = 2.96 atm
- P2 = 2.17 atm
- V1 = 2.25L
- V2 = 3.50L
- T1 = 298K
- T2 = ?
2.96 × 2.25/298 = 2.17 × 3.5/T2
0.022T2 = 7.595
T2 = 7.595 ÷ 0.022
T2 = 345.23K
Therefore, if a gas in a balloon occupies 2.25 L at 298 K and 300 kPa. the temperature at which the balloon expand to 3.50L and 2.17 atm is 345.23K.
Learn more about temperature at: brainly.com/question/11464844
