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olga2289 [7]
3 years ago
11

Which of the following is a buffer system? Which of the following is a buffer system? H2CO3(aq) and KHCO3(aq) NaCl(aq) and NaOH(

aq) H2O(l) and HCl(aq) HCl(aq) and NaOH(aq) NaCl(aq) and NaNO3(aq)
Chemistry
1 answer:
Readme [11.4K]3 years ago
3 0

Answer:

Explanation:

A buffer is defined as an aqueous mixture of a weak acid and its conjugate base or vice versa.

In the systems:

H₂CO₃(aq) and KHCO₃(aq): Carbonic acid, H₂CO₃, is a weak acid that, in solution with its conjugate pair, HCO₃⁻ make a <em>buffer system.</em>

NaCl(aq) and NaOH(aq): NaCl is a salt and NaOH is a strong base. Thus, this system <em>is not </em> a buffer system.

H₂O(l) and HCl(aq): Water is a solvent and HCl a strong acid. This <em>is not </em>a buffer system.

HCl(aq) and NaOH(aq): HCl is a strong acid and NaOH a strong base. This <em>is not </em>a buffer system.

NaCl(aq) and NaNO₃(aq): Both NaCl and NaNO₃ are salts and this system <em>is not </em>a buffer system.

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The graph given below shows the motion of four runners P, Q, R, and S in a 5 km marathon.
wel

Answer:-

As we can see from the graphical data,

The distance covered by all the four runners is the same 5 km.

Among the four athletes, Athlete P covers the distance in under three hours.

It is the minimum time taken among the four athletes.

Thus Athlete P covers the 5 km distance in the minimum amount of time.

We know that speed = \frac{Distance}{Time}

Since time taken for P is minimum, his speed is the maximum. P ran the fastest.

Time taken by Q = 4.5 hours.

Speed of Q = \frac{Distance}{Time taken by Q}

                     = \frac{5km}{4.5hour}

                    = 1.1 km/ hr

Time taken by R = 6 hours.

Speed of R = \frac{Distance}{Time taken by R}

                     = \frac{5km}{6hour}

                    = 0.8 km/ hr

3 0
3 years ago
A _____________ is formed when water empties into a lake or ocean
solong [7]

Answer:

a delta

Explanation:

he place where a river enters a lake, larger river, or the ocean is called its mouth. River mouths are places of much activity. As a river flows, it picks up sediment from the river bed, eroding banks, and debris on the water. ... When large amounts of alluvium are deposited at the mouth of a river, a delta is formed.

6 0
3 years ago
Which description best characterizes the motion of particles in a solid
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<span>The movement of particles within a solid is extremely slow when compared to that of a gas. It is also significantly slower in movement than that of the movement found within the particles of liquid. The more movement present and the faster the movement of the particles the more space will be present between each particle. This causes the material to spread out as they become less densely packed within a solid material.</span>
8 0
2 years ago
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Which of the following will float in gasoline
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Answer:

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Explanation:

I think the answer is balsa wood.

4 0
3 years ago
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Two bulbs are connected by a stopcock. The large bulb, with a volume of 6.00 L, contains nitric oxide at a pressure of 0.700 atm
ivolga24 [154]

Answer:

O_{2} and NO_{2}

Explanation:

For a given system at constant temperature, the number of moles of gas present in the system is proportional to the product of the system pressure and volume. Therefore, we have:

NO: 6 L * 0.7 atm = 4.2 L*atm

O:  1.5 L* 2.5 atm = 3.75 L*atm

For the given system based on a balanced chemical equation:

2.70 L*atm of nitric oxide reacts with (2.7/2) 1.35 L*atm of oxygen. This shows that there is more oxygen gas in the system than nitric oxide. Thus nitric oxide is the limiting reactant.

At the end of the experiment:

All the nitirc oxide has been used up, i.e. P_{NO} = 0

For the product: 2.70 L*atm NO produced  2.70 L*atm NO_{2}

The total volume of the system after the stopcock is opened = 6+1.5 = 7.5 L

The partial pressure of NO_{2}  = (2.70 L*atm NO_{2} ) / (7.5 L) = 0.36 atm NO_{2}  

Similarly for oxygen gas:

3.75 L*atm - 1.35 L*atm  = 2.40 L*atm oxygen gas remaining  

Partial pressure of oxygen is:

2.40 L*atm / 7.5 L = 0.32 atm  

Thus, the gases present at the end of the experiment are O_{2} and NO_{2}

3 0
3 years ago
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