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olga2289 [7]
3 years ago
11

Which of the following is a buffer system? Which of the following is a buffer system? H2CO3(aq) and KHCO3(aq) NaCl(aq) and NaOH(

aq) H2O(l) and HCl(aq) HCl(aq) and NaOH(aq) NaCl(aq) and NaNO3(aq)
Chemistry
1 answer:
Readme [11.4K]3 years ago
3 0

Answer:

Explanation:

A buffer is defined as an aqueous mixture of a weak acid and its conjugate base or vice versa.

In the systems:

H₂CO₃(aq) and KHCO₃(aq): Carbonic acid, H₂CO₃, is a weak acid that, in solution with its conjugate pair, HCO₃⁻ make a <em>buffer system.</em>

NaCl(aq) and NaOH(aq): NaCl is a salt and NaOH is a strong base. Thus, this system <em>is not </em> a buffer system.

H₂O(l) and HCl(aq): Water is a solvent and HCl a strong acid. This <em>is not </em>a buffer system.

HCl(aq) and NaOH(aq): HCl is a strong acid and NaOH a strong base. This <em>is not </em>a buffer system.

NaCl(aq) and NaNO₃(aq): Both NaCl and NaNO₃ are salts and this system <em>is not </em>a buffer system.

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A 2.241-g sample of nickel reacts with oxygen to form 2.852 g of the metal oxide.
nlexa [21]

Answer:

The empirical formula is = NiO

Explanation:

Given that:- Mass of nickel = 2.241 g

Mass of the oxide formed = 2.852 g

Mass of the oxygen reacted = Mass of the oxide formed - Mass of nickel  = 2.852 g - 2.241 g = 0.611 g

Molar mass of nickel  = 58.6934 g/mol

Moles of nickel = \frac{2.241}{58.6934}\ mol = 0.03818 mol

Molar mass of oxygen  = 15.999 g/mol

Moles of nickel = \frac{0.611}{15.999}\ mol = 0.03818 mol

Taking the simplest ratio for Ni and O as:

0.03818 : 0.03818 = 1 : 1

<u>The empirical formula is = NiO </u>

4 0
3 years ago
Consider the reaction 2NO(g) 1 O2(g) ¡ 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is reac
GalinKa [24]
<h2>a) The rate at which NO_2 is formed is 0.066 M/s</h2><h2>b) The rate at which molecular oxygen O_2 is reacting is 0.033 M/s</h2>

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of NO = -\frac{1d[NO]}{2dt} = 0.066 M/s

Rate in terms of disappearance of O_2 = -\frac{1d[O_2]}{dt}

Rate in terms of appearance of NO_2= \frac{1d[NO_2]}{2dt}

1. The rate of formation of NO_2

-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}

\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s

2. The rate of disappearance of O_2

-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}

-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s

Learn more about rate law

brainly.com/question/13019661

https://brainly.in/question/1297322

7 0
3 years ago
240 g of water (specific heat = 4.186 J/g°C, initial temperature = 20°C) is mixed with an
ivolga24 [154]
The answer for this would be 69.6
3 0
3 years ago
Covalent bonds take place between..
umka2103 [35]

Answer:

Covalent Bonds are formed when two non-metals share electrons

Hope this helps

7 0
3 years ago
Plz answer thx<br><br><br> ​How many moles are in 2.5 x 10^18 grams of water?
alex41 [277]

Answer:

1.39\times 10^{17} moles of water in 2.5\times 10^{18} g of water.

Explanation:

Mass of water = m = 2.5\times 10^{18} g

Molar mass of water = M = 18 g/mol

Moles = n = \frac{m}{M}

n=\frac{2.5\times 10^{18} g}{18 g/mol}=1.39\times 10^{17} moles

So, there are 1.39\times 10^{17} moles of water in 2.5\times 10^{18} g of water.

3 0
3 years ago
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