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zloy xaker [14]
3 years ago
15

Which factors can be multiplied together to make the trinomial 5x2 + 8x – 4? Check all that apply.

Mathematics
2 answers:
aivan3 [116]3 years ago
5 0
ANSWER

(5x - 2) \: and \: (x + 2)



EXPLANATION

To determine those factors , we need to factor the quadratic trinomial

5 {x}^{2}  + 8x - 4

We first multiply 5 by -4 to get,

5 \times ( - 4) =  - 20

Two factors of -20 that will add up to 8 are

- 2 \: and \: 10


We split the middle term with these factors.




5 {x}^{2}  + 10x - 2x - 4


We group and factor now to obtain,

5x(x + 2) - 2(x + 2)


We factor again to obtain,

(x + 2)(5x - 2)

Therefore the factors to be multiplied are,
(5x - 2) \: and \: (x + 2)
Taya2010 [7]3 years ago
5 0

Answer:

The factors are (x+2) and (5x-2).  [3 and 5 option]

Step-by-step explanation:

Given the trinomial 5x^2+8x-4

we have to find the factors of the above trinomial.

5x^2+8x-4

⇒ 5x^2-2x+10x-4

⇒ 5x^2-2x+10x-4

Taking x common from first two terms and 2 common from last two terms.

⇒ x(5x-2)+2(5x-2)

⇒ (x+2)(5x-2)

hence, the factors which can multiplied to make the trinomial are (x+2) and (5x-2)

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7 0
3 years ago
Sandra wrote the sequence shown:
-BARSIC- [3]

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2n^2 + n + 4.

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7, 14, 25, 40, 59

The differences  are 7, 11, 15, 19 which is  arithmetic sequence so the given sequence is quadratic.

Compile a table:

n                     1      2      3      4      5

term               7    14    25    40    59

Diff:                    7      11     15     19

Diff:                      4       4      4            - this indicates that first part is 2n^2.

2n^2               2    8    18    32     50

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= 5 + (n - 1)* 1

= n + 4.

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3 years ago
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