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Effectus [21]
3 years ago
11

Find the coordinates of point b on ac such that the ratio of AB to BC is 2:1

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
5 0

Answer:

(-2, 3)

Step-by-step explanation:

the point B is

B(x,y)

x

AB (A to B) is twice BC ( B to C )

AB is 2 - x. BC is x - (-4)= x + 4

So

2-x=2 (x + 4)

2-x=2x + 8

3x = -6

x = -2

y

(Same logic as above)

AB is -5 -y. BC is u - 7

-5 -y = 2(y - 7)

-5 - y = 2y - 14

3y = 9

y= 3

the point is (-2, 3)

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\bold{\huge{\red{\underline{Solution}}}}

\bold{\underline{ Given :- }}

  • We have given two figures that rectangle and parallelogram
  • The base and height of parallelogram is 7ft and 5ft
  • The length and breath of rectangle is 3ft and 1ft .

\bold{\underline{ To \: Find :- }}

  • We have to find the area of shaded part?

\bold{\underline{ Let's \: Begin :- }}

Firstly, we will calculate the area of parallelogram then area of rectangle after that we will subtract the area of rectangle from the area of parallelogram then we got the area of shaded part.

\sf{\pink{Area \:of\: parallelogram = Base * height }}

\sf { = 7 × 5 }

\sf { = 35ft }

\sf{ Thus,  \:The \:area\: of \:parallelogram\: is \:35ft}

\sf{\underline{ Now}}

\sf{\blue{Area\: of\: rectangle = L × B }}

\sf{ = 3 × 1 }

\sf{ = 3ft}

\sf{Thus, \:The\: Area\: of \:rectangle\: is\: 3ft}

\sf{\underline{ Now}}

\sf{ Total\: area \:of \:shaded\: part }

\sf{ Area\: of\: parallelogram - Area\: of\: rectangle }

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\bold{\pink{Hence, \: Area\: of \:shaded\: part \:is\: 32ft}}

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