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Effectus [21]
3 years ago
11

Find the coordinates of point b on ac such that the ratio of AB to BC is 2:1

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
5 0

Answer:

(-2, 3)

Step-by-step explanation:

the point B is

B(x,y)

x

AB (A to B) is twice BC ( B to C )

AB is 2 - x. BC is x - (-4)= x + 4

So

2-x=2 (x + 4)

2-x=2x + 8

3x = -6

x = -2

y

(Same logic as above)

AB is -5 -y. BC is u - 7

-5 -y = 2(y - 7)

-5 - y = 2y - 14

3y = 9

y= 3

the point is (-2, 3)

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Solve for x in the equation 2x2-5x+1=3
Butoxors [25]
2x^2 - 5x + 1 = 3

Subtract 3 from both sides
2x^2 - 5x + 1  - 3 = 3  - 3

2x^2 - 5x - 2 = 0

Use quadratic formula with A = 2,  B =  - 5,   C =  - 2

x =  - b +- sqrt b^2 - 4ac/2a

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Answer:  x = 5/4 + 1/4 sqrt 41
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