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sasho [114]
3 years ago
13

The measures of each exterior angle in a regular hexagon is (4x + 15)°. Find the value of x. Show equations and all work that le

ads to your answer.

Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer:

x=11.25

Step-by-step explanation:

Given that the measures of each exterior angle in a regular hexagon is (4x + 15)°.

Hexagon means there are 6 sides.

We know that sum of all exterior angles of a regular polygon is always 360 degree.

So if there are n sides of polygon then we can write formula:

nA=360

where n= number of sides = 6

A=(4x + 15)°  {given each interior angle is equal to (4x + 15)°}


plug these into above formula:

6(4x + 15)°=360°

4x + 15=60

4x = 45

4x = 45

x=11.25

<u>Hence final answer is x=11.25.</u>

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Darius wants to purchase his favorite salad dressing. The salad dressing comes in two different size bottles. The 16 ounce bottl
Leya [2.2K]

<u>Answer:</u>

The correct answer option is b. Darius will get the better deal buying one 16 ounce bottle.

<u>Step-by-step explanation:</u>

We know that a 16 ounce bottle of the salad dressing is for $3.36 while a 10 ounce bottle is priced at $2.30.

Darius has a coupon for 40 cents off if he buys two 10 ounce bottles. We are to determine what is the better buy.

Price of one 16 ounce bottle = $3.36

Price of two 10 ounce bottles = (2.30 × 2) - 0.4 = $4.2

Therefore, Darius will get the better deal buying one 16 ounce bottle.

7 0
3 years ago
Read 2 more answers
Determine the resulting polynomial: <br> f(x)=10x−5<br> g(x)=2x2+4x−4<br> Find: f(x)⋅g(x)
Lina20 [59]
40x^2 - 20x

(10x-5)(2*2+4x-4)
(10x-5)(4-4+4x)
(10x-5)(4x)
40x^2 - 20x
4 0
3 years ago
The sum of 4 consecutive integers is 110. Find the integers.
zloy xaker [14]

Answer:

26, 27, 28, 29

Step-by-step explanation:

Let the first integer be x.

Then, (x)+(x+1)+(x+2)+(x+3) = 110

=> x+x+1+x+2+x+3 = 110

=> 4x+6 = 110

=> 4x = 110-6

=> 4x = 104

=> x = 104/4

=> x = 26

So, the four consecutive integers are:

1. x = 26

2. x+1 = 26+1 = 27

3. x+2 = 26+2 = 28

4. x+3 = 26+3 = 29

8 0
2 years ago
Read 2 more answers
Given that these triangles are similar, what is the perimeter of triangle PQR? Show your work.
dimaraw [331]

Answer:

24

Step-by-step explanation:

I use the Pythagoras theorem.

\sqrt{a^{2} +b^{2} } =c^{2}

4^{2}{x}6^{2} = c^{2}

16 x 36= 576

\sqrt{576} = 24

6 0
3 years ago
Graph for f(x)=6^6 and f(x)=14^x
zlopas [31]

Graph Transformations

There are many times when you’ll know very well what the graph of a

particular function looks like, and you’ll want to know what the graph of a

very similar function looks like. In this chapter, we’ll discuss some ways to

draw graphs in these circumstances.

Transformations “after” the original function

Suppose you know what the graph of a function f(x) looks like. Suppose

d 2 R is some number that is greater than 0, and you are asked to graph the

function f(x) + d. The graph of the new function is easy to describe: just

take every point in the graph of f(x), and move it up a distance of d. That

is, if (a, b) is a point in the graph of f(x), then (a, b + d) is a point in the

graph of f(x) + d.

As an explanation for what’s written above: If (a, b) is a point in the graph

of f(x), then that means f(a) = b. Hence, f(a) + d = b + d, which is to say

that (a, b + d) is a point in the graph of f(x) + d.

The chart on the next page describes how to use the graph of f(x) to create

the graph of some similar functions. Throughout the chart, d > 0, c > 1, and

(a, b) is a point in the graph of f(x).

Notice that all of the “new functions” in the chart di↵er from f(x) by some

algebraic manipulation that happens after f plays its part as a function. For

example, first you put x into the function, then f(x) is what comes out. The

function has done its job. Only after f has done its job do you add d to get

the new function f(x) + d. 67Because all of the algebraic transformations occur after the function does

its job, all of the changes to points in the second column of the chart occur

in the second coordinate. Thus, all the changes in the graphs occur in the

vertical measurements of the graph.

New How points in graph of f(x) visual e↵ect

function become points of new graph

f(x) + d (a, b) 7! (a, b + d) shift up by d

f(x) Transformations before and after the original function

As long as there is only one type of operation involved “inside the function”

– either multiplication or addition – and only one type of operation involved

“outside of the function” – either multiplication or addition – you can apply

the rules from the two charts on page 68 and 70 to transform the graph of a

function.

Examples.

• Let’s look at the function • The graph of 2g(3x) is obtained from the graph of g(x) by shrinking

the horizontal coordinate by 1

3, and stretching the vertical coordinate by 2.

(You’d get the same answer here if you reversed the order of the transfor-

mations and stretched vertically by 2 before shrinking horizontally by 1

3. The

order isn’t important.)

74

7:—

(x) 4,

7c’

‘I

II

‘I’

-I

5 0
3 years ago
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