Children gender. a certain couple is equally likely to have either a boy child or a girl child. if the family has four children,
let x denote the number of girls.
a. identify the possible values of the random variable x.
b. determine the probability distribution of x. (hint: there are 16 possible equally-likely outcomes. one is gbbb, meaning the first born is a girl and the next three born are boys.
use random-variable notation to represent each of the following events. also use the special addition rule and the probability distribution obtained in part (b to determine each event’s probability. the couple has
c. exactly two girls.
d. at least two girls.
e. at most two girls.
f. between one and three girls, inclusive.
g. children all of the same gender.
1 answer:
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Answer:
x=1/4
Step-by-step explanation:
f(1/4)=0
1 and 23/100 because you can't simplify the fraction more than what it is. Remember what ever you do to the numerator you do to the denominator and vise versa
Answer:
0
Step-by-step explanation:
10r - 5r + 3r - 8r
all of these have the common term of r, therefore simple addition of the integers would get you the answer in terms of r
10-5+3-8=0
8+(-4)+(-3)=8-4-7
17.1
(-4)+(-4)+(-4)=(-4) X 3
20.(-12)
Not sure what you mean by drag and drop but Im going to attempt this.
-3/5 = -12/20
1/5 = 4/20
That makes no sense. It should be -8/20 < 7/20?
