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Llana [10]
3 years ago
11

Children gender. a certain couple is equally likely to have either a boy child or a girl child. if the family has four children,

let x denote the number of girls.
a. identify the possible values of the random variable x.
b. determine the probability distribution of x. (hint: there are 16 possible equally-likely outcomes. one is gbbb, meaning the first born is a girl and the next three born are boys.
use random-variable notation to represent each of the following events. also use the special addition rule and the probability distribution obtained in part (b to determine each event’s probability. the couple has
c. exactly two girls.
d. at least two girls.
e. at most two girls.
f. between one and three girls, inclusive.
g. children all of the same gender.
Mathematics
1 answer:
rusak2 [61]3 years ago
6 0
D. at least two girls
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Answer:

<em>The difference quotient of f is 8. </em><em>Option C</em>

Explanation:

<u>Difference Quotient</u>

Given a function f(x), the difference quotient is defined as

\displaystyle d=\frac{f(h+h)-f(x)}{h},\ h\neq 0

The function provided in the question is

f(x)=8x+1

Find f(x+h) by substituting x by x+h:

f(x+h)=8(x+h)+1

f(x+h)=8x+8h+1

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Operating:

\displaystyle d=\frac{8x+8h+1-8x-1}{h}

Simplifying:

\displaystyle d=\frac{8h}{h}

d=8

A.  Incorrect.

This choice is different from the answer.

B. Incorrect.

This choice is different from the answer.

C. Is correct

The difference quotient is 8 as explained above.

D. Incorrect.

This choice is different from the answer.

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