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3 years ago

What are the 4 sub levels and how many electrons can fit into each

1 answer:

5 0

Each sublevel is assigned a letter.
The four sublevels are:
· s (sharp)
· p (principle)
· d (diffuse)
· f (fine or fundamental)

The s (sharp) sublevel can hold 2 electrons.
The p (principle) sublevel can hold 6 electrons.
The d (diffuse) sublevel can hold 10 electrons.
The f (fine or fundamental) sublevel can hold 14 electrons.

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_______________ is when a compound containing carbon and hydrogen (and sometimes oxygen) combines with oxygen gas to produce car

kotykmax [81]

Answer:

C. Combustion

Explanation:

Combustion- an organic compound containing carbon, hydrogen and sometimes oxygen reacts with oxygen gas to form carbon dioxide and water.

4 0

4 years ago

PLEASE HELP!! 15 POINTS!<br> What could the fourth quantum number of a 2s^2 electron be?

Veronika [31]

Answer:

option D

Explanation:

first quantum number of a 2s2

n = 2

second quantum number of a 2s2

l = 0 to n-1

l = 0, 1

For s orbital

l = 0

third quantum number of a 2s2

ml = - l to +l

ml = 0

fourth quantum number of a 2s2 electron be

?½ = spin down

½ = spin up

2s2 has 2 electrons 1 spin down and 1 spin up (starts with spin down)

ms = +1/2

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3 years ago

Explain how Newton's idea about inertia has helped in astronomy?

lilavasa [31]

Answer:

the answer is A because when something is going straight it wont change unless its acted upon by a force

Explanation:

3 0

3 years ago

Read 2 more answers

A thin metallic spherical shell of radius 41.6 cm has a total charge of 8.55 μC uniformly distributed on it. At the center of th

Paul [167]

Answer:

E = 1.2443*10⁶ N/C

Explanation:

R = 41.6 cm = 0.416 m

Q₁ = 8.55 μC = 8.55*10⁻⁶C

Q₀ = 4.43 μC = 4.43*10⁻⁶C

r = 17.9 cm = 0.179 m

K = 9*10⁹ N*m²/C²

Since r < R we can apply Gauss's Law as follows

E = K*Q₀ / r²

⇒ E = (9*10⁹ N*m²/C²)*(4.43*10⁻⁶C) / (0.179 m)²

⇒ E = 1.2443*10⁶ N/C

5 0

3 years ago

A student reacted NiS2 (MM = 122.83 g/mol) with O2 (MM=32.00 g/mol) to make SO2 (MM=64.07 g/mol) according to this balanced equa

Ilya [14]

Answer:

Percentage yield = 0.49 × 10² %

Explanation:

Given data:

Actual yield of SO₂ = 4.309 ×10² g

Theoretical yield of SO₂ = 8.78 ×10² g

Percentage yield = ?

Solution:

Chemical equation:

2NiS₂ + 5O₂ → 2NiO + 4SO₂

Percentage yield:

Percentage yield = actual yield / theoretical yield × 100

Percentage yield = 4.309 ×10² g / 8.78 ×10² g × 100

Percentage yield = 0.491 × 100

Percentage yield = 49.1%

In scientific notation:

Percentage yield = 0.49 × 10² %

5 0

3 years ago