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Brut [27]
3 years ago
8

If you have 2 moles of an element, how many particles do you have?

Chemistry
1 answer:
Amanda [17]3 years ago
3 0

Answer:

1.204×10^24 particles of element

Explanation:

1mol=6.02×10^23 number of particles (in this case an element)

2mol=(6.02×10^23)×2 particles of the element

=1.204×10^24 particles of element

*be careful aware significant digits

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<u>Answer:</u> The number of moles of ammonium nitrate is 0.004 moles.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

We are given:

Molarity of NH_4NO_3 solution = 0.125 M

Volume of solution = 32.5 mL

Putting values in above equation, we get:

0.125M=\frac{\text{Moles of }NH_4NO_3\times 1000}{32.5mL}\\\\\text{Moles of }NH_4NO_3=0.004mol

Hence, the number of moles of ammonium nitrate is 0.004 moles.

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2 years ago
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xeze [42]

Answer:

Amount of Ca(NO3)2 produced = 14.02 g

Explanation:

The given reaction can be depicted as follows:

Ca(OH)2 + 2HNO3 → Ca(NO3)2 + 2H2O

Since it is given that HNO3 is in excess, the limiting reactant is Ca(OH)2

Now, Mass of Ca(OH)2 = 6.33 g

Molar mass of Ca(OH)2 = 74 g/mol

Moles\ Ca(OH)2 = \frac{Mass}{Molar\ Mass} = \frac{6.33 g}{74 g/mol} =0.0855

Based on the reaction stoichiometry:

1 mole of Ca(OH)2 forms 1 mole of Ca(NO3)2

Therefore, moles of Ca(NO3)2 produced from the moles of Ca(OH)2 reacted = 0.0855 moles

Molar mass of Ca(NO3)2 = 164 g/mol

Mass\ Ca(NO3)2 \ produced = moles*molar\ mass \\= 0.0855\ moles*164\ g/mol = 14.02\  g

6 0
4 years ago
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Answer: neutral

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