The drag force acting on the rocket is 80N.
<h3>Give an explanation of drag force?</h3>
The divergence in velocity between the fluid and the item, also known as drag, exerts a force on it. Between the liquid and the solid object, there should be motion. Drag is absent in the absence of motion.
The air molecules are more compressed (pushed together) on the surfaces that are facing the front while being more dispersed (spread out) on the surfaces facing the back. Turbulent flow, which occurs when air layers split from the surface and start to swirl, is what causes this.
The drag force acting on the rocket F = ma
Given,
m = 4kg, a = 20ftm/s²
Substituting m and a values in the above formula,
The drag force acting on the rocket F = 4×20
The drag force acting on the rocket F = 80N.
To know more about drag force visit:
brainly.com/question/15144984
#SPJ4
Answer:
Vf = 28 m/s
Explanation:
In order to find the final velocity of the rock, we will use the 3rd equation of motion. The third equation of motion for vertical direction is written as follows:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = height dropped = 40 m
Vf = final velocity of the rock = ?
Vi = Initial Velocity of the rock = 0 m/s (since, rock was initially at rest)
Therefore,
(2)(9.8 m/s²)(40 m) = Vf² - (0 m/s)²
Vf = √(784 m²/s²)
<u>Vf = 28 m/s</u>
Answer:
a. 25000 J
b. 2500 J/s
Explanation:
Given,
Distance ( s ) = 50 m
Force ( f ) = 500 N
a.
To find : -
Work done ( W ) = ?
Formula : -
W = fs
W
= 500 x 50
= 25000 J
Therefore,
the work done by the force the horse exerts is
25000 J.
b.
To find : -
Power ( P ) = ?
Formula : -
W = Pt
P = W / t
P
= 25000 / 10
= 2500 J/s
Therefore,
the power produced if the movement took 10 s
is 2500 J/s.
<span>Correlations allow you to make inferences.</span>
The work done to stop the car is -208.33 kJ
From work-kinetic energy principles, the change in kinetic energy of the car ,ΔK equals the work done to stop the car, W.
W = ΔK = 1/2m(v'² - v²) where
- m = mass of car = 1500 kg,
- v = initial velocity of car = 60 km/h = 60 × 1000 m/3600 s = 16.67 m/s and
- v' = final velocity of car = 0 m/s (since the car stops).
<h3 /><h3>Calculating the work done</h3>
Substituting the values of the variables into the equation, we have
W = 1/2m(v'² - v²)
W = 1/2 × 1500 kg(v(0 m/s)² - (16.67 m/s)²)
W = 750 kg(0 (m/s)² - 277.78 (m/s)²)
W = 750 kg(- 277.78 (m/s)²)
W = -208333.33 J
W = -208.33333 kJ
W ≅ -208.33 kJ
So, the work done to stop the car is -208.33 kJ
Learn more about work done here:
brainly.com/question/9821607
