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3 years ago

5

The talk test can be used to measure the __________. A. knowledge of an activity B. intensity of an activity C. length of an act

ivity D. cost of an activity

2 answers:

postnew [5]3 years ago

8 0

Yeah I also think it’s a or b

aivan3 [116]3 years ago

5 0

I would say A or B if there’s a text can u post that as well but I’m just going by what it sound like

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The chart below shows the dates of eclipses in the years 2006 and 2007. What is the best explanation for the frequency of eclips

xz_007 [3.2K]

Answer:

It's A

As the Gizmo shows, the Moon orbits at an angle relative to the plane of Earth's orbit. Usually, the Moon is above or below the Earth when an eclipse could happen. Every six months or so, the Moon, Earth and Sun are lined up sufficiently to create a lunar and a solar eclipse.

4 0

3 years ago

If tje object is placed pf the focus of a concave mirror the image is formed....

gavmur [86]

Answer:

with the mirror into the right direction

Explanation:

4 0

3 years ago

Read 2 more answers

A satellite is in a circular Earth orbit of radius r. The area A enclosed by the orbit depends on r2 because A = πr2. Determine

Salsk061 [2.6K]

Answer:

a. $T=r^{3/2}$

b. $K=\frac{1}{r}$

c. $v=\frac{1}{\sqrt{r}}$

d. $v=\sqrt{r}$

Explanation:

To make analysis about the satellite circular earth the depends or r and A

$T^2=\frac{4\pi}{GM}*r^3$

$K=\frac{GM*m}{2*r}$

a.

$T^2=r^3$

$T=r^{3/2}$

b.

$K=\frac{GM*m}{2}*\frac{1}{r}$

$K=\frac{1}{r}$

c.

$K=\frac{1}{2}*m*v^2$

$v^2=\frac{2*K}{m}=\frac{2*Gm*m}{2*m*r}$

$v=\frac{1}{\sqrt{r}}$

d.

$v=\sqrt{2*GMr}$

$v=\sqrt{r}$

3 0

3 years ago

Critical Thinking

Sophie [7]

OK.

You're sitting in a soft comfy chair, reading a book in your lap.
The book stays put, and you eventually start to get sleepy, because
there's almost no acceleration happening.

The chair you're sitting in is seat #27B in a huge jet taking you to visit
your grandparents who live a thousand miles away.
The airplane is maybe 7 miles up, passing over the ground at nearly
500 miles per hour, flying straight, level, and fast !

6 0

3 years ago

Can y’all please help me with this 3 part question?

klio [65]

Answer:

Vf = 210 [m/s]

Av = 105 [m/s]

y = 2205 [m]

Explanation:

To solve this problem we must use the following formula of kinematics.

$v_{f} =v_{o} +g*t$

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (released from the rest)

g = gravity acceleration = 10 [m/s²]

t = time = 21 [s]

Vf = 0 + (10*21)

Vf = 210 [m/s]

Note: The positive sign for the gravity acceleration means that the object is falling in the same direction of the gravity acceleration (downwards)

The average speed is defined as the sum of the final speed plus the initial speed divided by two. (the initial velocity is zero)

Av = (210 + 0)/2

Av = 105 [m/s]

To calculate the distance we must use the following equation of kinematics

$v_{f} ^{2} =v_{o} ^{2} +2*g*y\\\\(210)^{2} = 0 + (2*10*y)$

44100 = 20*y

y = 2205 [m]

5 0

3 years ago