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Sonja [21]
3 years ago
14

When a wave travels through a medium, the wave transfers

Physics
1 answer:
Pavel [41]3 years ago
4 0

Answer: 2

Explanation: waves transfer energy without transferring mass

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Can someone help please and thank you:)
Ray Of Light [21]

Answer:

The answer is C.

Explanation:

4 0
3 years ago
a college student produces about 100 kcal of heat per hour on the average what is the rate of energy production and joules
Bond [772]

Given:

Amount of heat produced = 100 kcal per hour

Let's find the rate of energy production in joules.

We know that:

1 calorie = 4.184 Joules

1 kcal = 4.184 Joules

To find the rate of energy production in Joules, we have:

\begin{gathered} Rate=100\ast4.184 \\  \\ \text{Rate}=418.4\text{ KJ/hour} \end{gathered}

Therefore, the rate of energy production in joules is 418.4 kJ/h which is equivalent to 418400 Joules

ANSWER:

418.4 kJ/h

6 0
1 year ago
Which of the following describes the variable that responds to a change?
timama [110]
Dependent variable is your answer.
8 0
3 years ago
Read 2 more answers
You place a large pebble in a slingshot, pull the elastic band back to your chin, and release it, launching the pebble horizonta
sladkih [1.3K]

Answer:

The larger pebble has 25 times more mass.

Explanation:

To solve the exercise it is necessary to apply the work and energy conservation equations.

For the case described, the work done must be preserved and must be the same, that is,

W = 0

By definition work linked to the conservation of kinetic energy would be given by

\Delta KE = W = 0

\Delta KE = 0

KE_{larger}-KE_{smaller} = 0

KE_{larger}=KE_{smaller}

\frac{1}{2}m_lv_l^2 = \frac{1}{2}m_sv_s^2

m_lv_l^2 = m_sv_s^2

The ratio between the mass and the velocity would be,

\frac{m_l}{m_s}=\frac{v_s^2}{v_l^2}

\frac{m_l}{m_s} = \frac{500^2}{100^2}

\frac{m_l}{m_s} = 25

Therefore the answer is: The larger pebble has 25 times more mass.

4 0
3 years ago
How far does a ca4 go
miv72 [106K]

Answer:

as far as the car can withstand

Explanation:

5 0
3 years ago
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