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2 years ago

Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60km/h

Physics

1 answer:

natima [27]2 years ago

4 0

The work done to stop the car is -208.33 kJ

From work-kinetic energy principles, the change in kinetic energy of the car ,ΔK equals the work done to stop the car, W.

W = ΔK = 1/2m(v'² - v²) where

m = mass of car = 1500 kg,
v = initial velocity of car = 60 km/h = 60 × 1000 m/3600 s = 16.67 m/s and
v' = final velocity of car = 0 m/s (since the car stops).

<h3 /><h3>Calculating the work done</h3>

Substituting the values of the variables into the equation, we have

W = 1/2m(v'² - v²)

W = 1/2 × 1500 kg(v(0 m/s)² - (16.67 m/s)²)

W = 750 kg(0 (m/s)² - 277.78 (m/s)²)

W = 750 kg(- 277.78 (m/s)²)

W = -208333.33 J

W = -208.33333 kJ

W ≅ -208.33 kJ

So, the work done to stop the car is -208.33 kJ

Learn more about work done here:

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2 years ago

Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60km/h​

Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60km/h