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Paul [167]
2 years ago
14

Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60km/h​

Physics
1 answer:
natima [27]2 years ago
4 0

The work done to stop the car is -208.33 kJ

From work-kinetic energy principles, the change in kinetic energy of the car ,ΔK equals the work done to stop the car, W.

W = ΔK = 1/2m(v'² - v²) where

  • m = mass of car = 1500 kg,
  • v = initial velocity of car = 60 km/h = 60 × 1000 m/3600 s = 16.67 m/s and
  • v' = final velocity of car = 0 m/s (since the car stops).
<h3 /><h3>Calculating the work done</h3>

Substituting the values of the variables into the equation, we have

W = 1/2m(v'² - v²)

W = 1/2 × 1500 kg(v(0 m/s)² - (16.67 m/s)²)

W = 750 kg(0 (m/s)² - 277.78 (m/s)²)

W = 750 kg(- 277.78 (m/s)²)

W = -208333.33 J

W = -208.33333 kJ

W ≅ -208.33 kJ

So, the work done to stop the car is -208.33 kJ

Learn more about work done here:

brainly.com/question/9821607

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<h2>17.6 feet / second ^2</h2>

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THAT's exactly a chemical change.

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3 years ago
The bar graph shows energy data taken from a roller coaster at a theme park. analyze the data and assess its validity. 3-5 sente
hichkok12 [17]

This question involves the concepts of the law of conservation of energy, potential energy, and kinetic energy.

The data shown by the bar graph is "valid".

According to the law of conservation of energy, the total energy of the system must remain constant at any given point. Hence, the sum of the kinetic energy and the potential energy of the roller coaster must be constant at any given time.

Considering the bottom of the first hill:

Total Energy at 1st Hill = Kinetic Energy + Potential Energy

From the data given in the bar graph:

Total Energy at 1st Hill = 2,500,000 J + 0 J (since at the bottom potential energy is zero due to zero height)

Total Energy at 1st Hill = 2,500,000 J

Now, considering the top of the second hill:

Total Energy at 2nd Hill = Kinetic Energy + Potential Energy

From the data given in the bar graph:

Total Energy at 2nd Hill = 1,000,000 J + 1,500,000 J

Total Energy at 2nd Hill = 2,500,000 J

Hence,

Total Energy at 1st Hill = Total Energy at 2nd Hill

Therefore, the given bar graph is "valid".

Learn more about the law of conservation of energy here:

brainly.com/question/20971995?referrer=searchResults

The attached picture explains the law of conservation of energy.

4 0
2 years ago
How do I solve such problem???
pashok25 [27]

As far as I'm concerned, this is a bogus question, or at least a severely corrupted one.

The three numbers given can NOT all be true on Earth.

-- It rolled off the table at 7.6 m/s .  By golly, there you are!  Its initial horizontal velocity is 7.6 m/s, and it has no vertical velocity until it leaves the table.

-- There are no horizontal forces that we're aware of acting on the object.  So it maintains the same horizontal velocity for the rest of the story.  It's 10.5m away from the table in (10.5 m) / (7.8 m/s) = 1.35 second .

-- Vertically, it's just an object dropped from 17.6m off the floor.  Shockingly, the distance it falls in time 'T' is (1/2 g) T².  In 1.35 second, that's 8.88 meters ! . . . only about halfway to the floor !

-- In order to fall 17.6 m to the floor, it would need 1.89 seconds.  In <u>that</u> length of time, however, it would travel (7.8 m/s) x (1.89 s) = 14.78 m away from the base of the table.

So you see, either . . .

-- the table is NOT 17.6m tall, or

-- the object does NOT roll off of the table at 7.8 m/s, or

-- it does NOT land 10.5 m away from the base of the table.

OR . . .

-- the table is not on Earth, and gravity is not 9.8 m/s² !

We often see questions posted on Brainly with not enough given information, OR with some information given that's not needed because it's not involved the answer.  

THIS one is different, and it's unusual.  In this one, we have<em> too much</em> given information, we can't ignore any of it because it's all related, but it's inconsistent and it CAN't all be true.

(Unless the whole story takes place on a mystery planet that is not Earth.  Which I'm not going to take the time and effort right now to figure out what the acceleration of gravity has to be in order to make all of the given information compatible.)

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