Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60km/h

Physics

1 answer:

natima [27]2 years ago

4 0

The work done to stop the car is -208.33 kJ

From work-kinetic energy principles, the change in kinetic energy of the car ,ΔK equals the work done to stop the car, W.

W = ΔK = 1/2m(v'² - v²) where

m = mass of car = 1500 kg,
v = initial velocity of car = 60 km/h = 60 × 1000 m/3600 s = 16.67 m/s and
v' = final velocity of car = 0 m/s (since the car stops).

<h3 /><h3>Calculating the work done</h3>

Substituting the values of the variables into the equation, we have

W = 1/2m(v'² - v²)

W = 1/2 × 1500 kg(v(0 m/s)² - (16.67 m/s)²)

W = 750 kg(0 (m/s)² - 277.78 (m/s)²)

W = 750 kg(- 277.78 (m/s)²)

W = -208333.33 J

W = -208.33333 kJ

W ≅ -208.33 kJ

So, the work done to stop the car is -208.33 kJ

Learn more about work done here:

brainly.com/question/9821607

You might be interested in

The ceiling of your lecture hall is probably covered with acoustic tile, which has small holes separated by about 5.9 mm. Using

timurjin [86]

Answer:

45.88297 m

Violet

Explanation:

x = Gap between holes = 5.9 mm

$\lambda$ = Wavelength = 527 nm

D = Diameter of eye = 5 mm

L= Distance of observer from holes

From Rayleigh criteria we have the relation

$\frac{x}{L}=1.22\frac{\lambda}{D}\\\Rightarrow L=\frac{xD}{1.22\lambda}\\\Rightarrow L=\frac{5.9\times 10^{-3}\times 5\times 10^{-3}}{1.22\times 527\times 10^{-9}}\\\Rightarrow L=45.88297\ m$

A person could be 45.88297 m from the tile and still resolve the holes

Resolving them better means increasing the distance between the observer and the holes. It can be seen here that the distance is inversely proportional to the wavelength. Violet has a lower wavelength than red so, violet light would resolve the holes better.

5 0

3 years ago

Kelli weighs 425 N, and she is sitting on a playground swing that hangs 0.36 m above the ground. Her mom pulls the swing back an

kodGreya [7K]

Answer:

V = 3.54 m/s

Explanation:

Using the conservation of energy:

$E_i = E_f$