Answer:
a) Warmer
b) Exothermic
c) -10.71 kJ
Explanation:
The reaction:
KOH(s) → KOH(aq) + 43 kJ/mol
It is an exothermic reaction since the reaction liberates 43 kJ per mol of KOH dissolved.
Hence, the dissolution of potassium hydroxide pellets to water provokes that the beaker gets warmer for being an exothermic reaction.
The enthalpy change for the dissolution of 14 g of KOH is:

<u>Where:</u>
m: is the mass of KOH = 14 g
M: is the molar mass = 56.1056 g/mol

The enthalpy change is:

The minus sign of 43 is because the reaction is exothermic.
I hope it helps you!
Answer:
NH₄Cl (aq) + NaOH (aq) -> NaCl (aq) + H₂O (l) + NH₃ (g)
(NH₄)₂CO₃ (aq) + 2KOH (aq) -> K₂CO₃ (aq) + 2H₂O (l) + 2NH₃(g)
NH₄NO₃ (aq) + LiOH (aq) -> LiNO₃ (aq) + H₂O (l) + NH₃ (g)
Explanation:
The gas liberated when an alkali reacts with an ammonium salt is NH₃ (ammonia), not CO₂.
Answer:
in terms of chemistry, the forward reaction balances the backward reaction :)
Explanation:
Answer:
Al(OH)- 4,
Explanation:
NaOH added to 0.010 M Al3+
The predominant species at equilibrium will be = Al(OH)- 4, and this because sodium hydroxide ( NaOH ) is a base will readily form a stable complex ion with aluminum ion like ( Al( OH ) - 4 . also the higher the Kf value the more stable the complex ion becomes and the more soluble Al(OH)3 becomes
hence the predominant species at equilibrium is : Al(OH)- 4,