Answer:
Determine how many moles of CO2 are required to produce 11.0 mol of glucose,
i need points thanks for CO2moles
Answer:
Explanation:
The given number is 6.02 × 10⁹. It is written is scientific notation.
As you see it has two parts:
- The first part are the digits with the decimal point after the first digit. This part is called mantissa. The mantissa can only have one digit, between 1 and 9, before the decimal point.
- The second part is a power of 10. The exponent can be either positive or negative.
If the exponent is negative means that the decimal point must be moved to the left and if the exponent is positive means that the decimal point must be moved to the right.
In the number 6.02 × 10⁹ the exponent is 9, so you must move the decimal point 9 places to the right:
- 6.02 × 10⁹ = 6.02 × 1,000,000,000 - 6,020,000,000,
Answer: 2.8275grams
Explanation: A buffer is made btw a weak acid and it salt. In a solution made by dissolving a weak acid in solution, equilibrium is set up btw ionised and unionised ion. For Benzoic acid
C6H5COOH....> C6H5COO- + H+
Ka = [C6H5COO-] [H+]/ [C6H5COOH].......(1)
using Ka = 6.5× 10^-5, [C6H5COOH] = 0.02M. PH= - log[H+] ....> [H+]= 10^-4M.
Putting the values in(1)
[C6H5COO-]= 6.5× 10^-5 × 0.02/ 10^-4
[C6H5COO-] = 0.013M = Molarity of sodium benzoate
Mole(C6H5COONa) = 0.013 × Volume = 0.013mol/litre × 1.5 litre
Mole(C6H5COONa) = 0.0195mol
Mass(C6H5COONa) = 0.0195 × Molar mass
Mass(C6H5COONa) = 2.8275g
Answer:
B) decreasing entropy is a non-spontaneous process
Explanation:
