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djyliett [7]
3 years ago
13

Can someone please help me how to set this up?

Physics
2 answers:
fiasKO [112]3 years ago
5 0
The car has a 12 mile head start, going 80 mph, so his distance is:dcar=80∗t+12
The is going at 108 mph, so his distance is:dcop=108t
Setting them equal to each other we get:80t+12=108t⇒12=28t⇒t=1228=37
So 3/7 of an hour.about 25.7 mins.
Citrus2011 [14]3 years ago
3 0

Answer:

The time is 0.428 hr.

Explanation:

Given that,

Final speed = 108 mph

Initial speed = 80 mph

Distance = 12 miles

We need to calculate the time

Using formula of time

v = \dfrac{d}{t}

d = distance

t = time

Put the value into the formula

108-80=\dfrac{12}{t}

t = \dfrac{12}{108-80}

t =0.428\ hr

Hence, The time is 0.428 hr.

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The hill is a total of 150 meters tall

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How is speed determined?
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For example if it takes someone three minutes to go three miles their speed is one mile a minute.

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In order to measure current in a circuit, the multi-meter needs to be placed in __A__ , while when measuring voltage, the multi-
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A- series B- parallel

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Voltmeter is connected in parallel to the load due to high value of current possessed by the voltmeter. The parallel connection will cause the current flowing through the voltmeter to reduce to zero so that it won't have effect (increase) on the amount of current initially on the resistor thereby measuring the exact amount of voltage on the load.

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4 years ago
In one or two sentences, explain design modifications which were implemented after the tacoma bridge disaster
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<h3>Why Tacoma Bridge disaster occurred?</h3>

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Because of the disaster of the Tacoma Narrows Bridge, the bridge was strengthened by adding trusses as well as openings below road decks so as to decrease vibrations caused by running vehicles on the bridge.

Thus, the modifications that are implemented after Tacoma bridge disaster are added trusses and openings below road decks to decrease oscillations

Learn more about Tacoma Bridge disaster.

brainly.com/question/17924109

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What is the bump on the lateral side just proximal to the 5th metatarsal?
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