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VMariaS [17]
3 years ago
9

A car accelerates from rest at -3.00m/s^2. What is the velocity at the end of 5.0s? What is the displacement after5.0s?

Physics
1 answer:
Andrew [12]3 years ago
5 0

Speed = (acceleration) x (time)
Velocity = (speed) in (direction of the speed)

Speed = (-3 m/s²) x (5 s) = 15 m/s
Velocity =
             (15 m/s) in the direction opposite to the direction you call positive
.

Displacement = (distance between start-point and end-point)
                           in the direction from start-point to end-point.

Distance = (1/2) (acceleration) (time)²
Distance = (1/2) (3 m/s²) (5 s)²
                 = (1/2) (3 m/s²) (25 s²)  =  37.5 meters

Displacement =
                     37.5 meters in the direction opposite to the direction you call positive.

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maria [59]

Answer:

<h2>17.1 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

3800 g = 3.8 kg

We have

force = 3.8 × 4.5

We have the final answer as

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Hope this helps you

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Montano1993 [528]
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blagie [28]

Answer:

Option A is correct.

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Explanation:

Option A is correct. (The faster object encounters more resistance)

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