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shusha [124]
3 years ago
6

imagine riding a single-speed bicycle. why do you have to push harders on the pedals to start the bicycle moving than to keep it

moving at constant velocity ?
Physics
1 answer:
Flura [38]3 years ago
3 0
A large force is required to accelerate the mass of the bicycle and rider. Once the desired constant velocity is reached, a much smaller force is sufficient to overcome the ever-present frictional forces. 
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A doorframe is twice as tall as it is wide. There is a positive charge on the top left corner and an equal but negative charge i
Andrei [34K]

Answer:

α = 141.5°  (counterclockwise)

Explanation:

If

q₁ = +q

q₂ = -q

q₃ < 0

b = 2*a

We apply Coulomb's Law as follows

F₁₃ = K*q₁*q₃ / d₁₃² = + K*q*q₃ / (2*a)² = + K*q*q₃ / (4*a²)

F₂₃ = K*q₂*q₃ / d₂₃² = - K*q*q₃ / (5*a²)

(d₂₃² = a² + (2a)² = 5*a²)

Then

∅ = tan⁻¹(2a/a) = tan⁻¹(2) = 63.435°

we apply

F₃x = - F₂₃*Cos ∅ = - (K*q*q₃ / (5*a²))* Cos 63.435°

⇒  F₃x = - 0.0894*K*q*q₃ / a²

F₃y = - F₂₃*Sin ∅ + F₁₃

⇒  F₃y = - (K*q*q₃ / (5*a²))* Sin 63.435° + (K*q*q₃ / (4*a²))

⇒  F₃y = 0.0711*K*q*q₃ / a²

Now, we use the formula

α = tan⁻¹(F₃y / F₃x)

⇒  α = tan⁻¹((0.0711*K*q*q₃ / a²) / (- 0.0894*K*q*q₃ / a²)) = - 38.5°

The real angle is

α = 180° - 38.5° = 141.5°  (counterclockwise)

4 0
4 years ago
the resistivity of gold is 2.44×10−8Ω⋅m at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a cur
cricket20 [7]

Answer:

0.03605 V/m is the electric field in the gold wire.

Explanation:

Resistivity of the gold = \rho = 2.44\times 10^{-8} \Omega.m

Length of the gold wire = L = 14 cm = 0.14 m ( 1 cm = 0.01 m)

Diameter of the wire = d = 0.9 mm

Radius of the wire = r = 0.5 d = 0.5 × 0.9 mm = 0.45 mm = 0.45\times 0.001 m

( 1mm = 0.001 m)

Area of the cross-section = A=\pi r^2=\pi r^(0.45\times 0.001 m)^2

Resistance of the wire = R

Current in the gold wire = 940 mA = 0.940 A ( 1 mA = 0.001 A)

R=\rho\times \frac{L}{A}

V(voltage)=I(current)\times R(Resistance) ( Ohm's law)

\frac{V}{I}=\rho\times \frac{L}{A}

We know, Electric field is given by :

E=\frac{dV}{dr}

E=\frac{V}{L}

E=\frac{V}{L}=\rho\times \frac{I}{A}

E=2.44\times 10^{-8} \Omega.m\times \frac{0.940 A}{\pi r^(0.45\times 0.001 m)^2}=0.03605 V/m

0.03605 V/m is the electric field in the gold wire.

3 0
3 years ago
Q.1 How long is an adult's small intestine?
Sloan [31]
I think The answer is d
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3 years ago
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The _______ principle encourages us to resolve a set of stimuli, such as trees across a ridgeline, into smoothly flowing pattern
kotegsom [21]

Answer:

The answer is continuity ( D )

Explanation:

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3 years ago
Acceleration can be found by computing the slope of a blank vs .time graph
scoundrel [369]
Velocity-time graph
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3 years ago
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