How many grams are in 9.05 x 1023 atoms of silicon?

Chemistry

1 answer:

Sergeu [11.5K]2 years ago

6 0

Explanation:

Number of moles(n)=Number of atoms(N)/Avogadro's constant.

Avogadro's constant=6.02×10²³

so we have

n=9.05×10²³/6.02×10²³

n=1.0503moles.

n=mass/molar mass

1.0503=mass/28

mass=1.0503×28

mass=29.4084g

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