A researcher is analyzing data from a high-energy particle collision. the result of the analysis gives a value of 8.8 x 10-19 c
1 answer:
Elementary charge used to determine charges of other objects is equal to a charge of electron or proton. It's value is roughly 
. All other charges are whole-number multipliers of this elementary charge, meaning that we multiply elementary charge by {...,-2,-1,0,1,2,...}.
To find out if the measured charge can be accepted we need to divide it with elementary charge to see if we get whole number as result.
There are three possible values of measured charge:
As we can see none of the possible values of a measured charge is whole-number multiplier of elementary charge so the researcher should not accept the value.
This charge can be achieved by using quarks which have value of 1/3 of elementary charge but they do not remain stable for long enough.
To find out if the measured charge can be accepted we need to divide it with elementary charge to see if we get whole number as result.
There are three possible values of measured charge:
As we can see none of the possible values of a measured charge is whole-number multiplier of elementary charge so the researcher should not accept the value.
This charge can be achieved by using quarks which have value of 1/3 of elementary charge but they do not remain stable for long enough.
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(a) 18.9 m/s
The motion of the stone consists of two independent motions:
- A horizontal motion at constant speed
- A vertical motion with constant acceleration () downward
We can calculate the components of the initial velocity of the stone as it is launched from the ground:
The horizontal velocity remains constant, while the vertical velocity changes due to the acceleration along the vertical direction.
When the stone reaches the top of its parabolic path, the vertical velocity has became zero (because it is changing direction): so the speed of the stone is simply equal to the horizontal velocity, therefore
(b) 22.2 m/s
We can solve this part by analyzing the vertical motion only first. In fact, the vertical velocity at any height h during the motion is given by
(1)
where
is the initial vertical velocity
is the vertical velocity at height h
is the acceleration due to gravity (negative because it is downward)
At the top of the parabolic path, , so we can use the equation to find the maximum height
So, at half of the maximum height,
And so we can use again eq(1) to find the vertical velocity at h = 6.9 m:
And so, the speed of the stone at half of the maximum height is
(c) 17.4% faster
We said that the speed at the top of the trajectory (part a) is
while the speed at half of the maximum height (part b) is
So the difference is
And so, in percentage,
So, the stone in part (b) is moving 17.4% faster than in part (a).
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