C4H8O (molecular)
CH3CH2C(O)CH3 (structural) just incase its needed.
Answer:
pH = 11.36
Explanation:
Before the addition of any HCl, you have 0.300M NH₃ in equilibrium with water:
NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)
When system is in equilibrium:
Kb = 1.8x10⁻⁵ = [NH₄⁺] [OH⁻] / [NH₃]
Concentrations in equilibrium are:
[NH₃] = 0.300M - X
[NH₄⁺] = X
[OH⁻] = X
1.8x10⁻⁵ = [X] [X] / [0.300M - X]
5.4x10⁻⁶ - 1.8x10⁻⁵X = X²
X² + 1.8x10⁻⁵X - 5.4x10⁻⁶ = 0
Solving for X:
X = -0.00233 → False answer, there is no negative concentrations
X = 0.00231 → Right answer.
As [OH⁻] = X; [OH⁻] = 0.00231
As pOH = -log [OH⁻] = 2.636
14 = pOH + pH
14 - pOH = pH
<em>pH = 11.36 </em>
Answer:
1. Iron(iii) hydroxide
2. It is a base
Explanation:
To determine the name of the compound, we must find the oxidation number Fe in the compound since the oxidation number of O is —2 in all its compound except for peroxide where it —1 and the oxidation number of Hydrogen is always +1 in all its compounds except for hydrides where it is —1. The oxidation number of Fe can calculated as follows:
Fe(OH)3 = 0
O = —2
H = +1
Fe =?
Fe + 3( —2 + 1) = 0
Fe + 3(—1) = 0
Fe —3 = 0
Fe = 3
The oxidation number of Fe in Fe(OH)3 is 3.
Therefore, the name of Fe(OH)3 is Iron(iii) hydroxide
Fe(OH)3 is a base since it contains the OH group
Answer:
Solution with a pH = 1
Explanation:
So the pH equation is pH = -log[H+]. To get the [H+] (hydrogen ion concentration), you rearrange to get [H+] = 10^-pH.
Solution with a pH = 1
, [H+] = .1 M
Solution with a pH = 12
, [H+] = 1*10^-12 M
Solution with a pH = 7
, [H+] = 1*10^-7 M
Solution with a pH = 9
, [H+] = 1*10^-9 M
Solution with a pH = 5, [H+] = 1*10^-5 M
Another way to get the answer: a high hydrogen ion concentration means that the solution should be more acidic. The most acidic pH of the 5 solutions is the one with a pH = 1.