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dimulka [17.4K]
4 years ago
6

a particular compound has the empirical formula CH2O. its molar mass is 240.0 g/mol. predict the molecular formula for this comp

ound.
Chemistry
1 answer:
jarptica [38.1K]4 years ago
7 0
<span>The molecular formula is 8(CH2O)= C8H16O8.</span>
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Conociendo el volumen de la solución y la masa del soluto y su masa molar, ¿qué concentración es posible determinar
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Answer:

Conociendo el volumen de solución, masa de soluto y su masa molar, es posible determinar: B) Concentración molar

La molaridad es la relación entre el número de moles de soluto y los litros de solución. Más:

M = No moles de solución de soluto / volumen (L)

Y a su vez los moles de soluto se encuentran por:

No moles de soluto = masa soluto / masa molar soluto

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Determine the concentration of nh3(aq) that is required to dissolve 743 mg of agcl(s) in 100.0 ml of solution. the ksp of agcl i
AnnyKZ [126]

Answer:

1.1 M

Explanation:

The dissociation of AgCl_{(s)} is as follows:

AgCl \leftrightharpoons Ag^+_{(aq)}+Cl^-_{(aq)}

Given Value for K_{sp} = 1.77*10^{-10}

The equation for the reaction for the formation of complex ion Ag(NH_3)^+_2 is :

Ag^+_{(aq)}    +     2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)}

The value of K_f = 1.6*10^7

If we combine both equation and find the overall equilibrium constant will be:

AgCl \leftrightharpoons Ag^+_{(aq)}+Cl^-_{(aq)}

Ag^+_{(aq)}    +     2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)}

<u>                                                                                                      </u>

AgCl_{(s)}+2NH_3_{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)} + Cl^-_{(aq)}

                                 K = (1.77*10^{-10})(1.6*10^7)

                                  K = 0.00283

If [NH_3] = x M

The solubility of  AgCl_{(s)} in the NH_3 solution will be:

x = 743*10^{-3}g * \frac{mol AgCl}{143.32g}*\frac{1}{0.1000L}

x = 0.0518 M

Constructing an ICE Table; we have :

                             AgCl_{(s)} + 2 NH_3{(aq)} \rightleftharpoons Ag(NH_3)_2^+_{(aq)} + Cl^-_{(aq)}

Initial  (M)                                     x                   0                      0

Change  (M)                       -2 (0.0518)      + 0.0518          + 0.0518

Equilibrium (M)                    x - 0.1156          0.0518             0.0518

Equilibrium constant;

(K) = \frac{[Ag(NH_3)_2^+][Cl^-]}{[NH_3]^2}

0.00283 = \frac{(0.0518)^2}{(x-0.1156)^2}

0.00283 = (\frac{0.0518}{x-0.1156})^2

x = 0.1156 + \sqrt{\frac{0.0518^2}{0.00283} }

x = [NH₃] =  1.089 M

[NH₃] ≅ 1.1 M                

8 0
3 years ago
Why is the periodic table called the periodic table
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The periodic table is named as such as it is split into groups with the same number of electrons in the outer shell. These groups can also be called periods which is where the table gets its name from.
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3 years ago
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