Answer:

Explanation:
Hello,
In this case, by considering the mathematical definition of by mass percentage of a solute as shown below:

We are able to compute the mass of the solute in a 20% solution having 500 g of solution as follows:

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CH4+(x)O2=CO2 +(Y)H2O
C=1 +H=4 +O=? = C=1 +O=2+? +H=?
H=4>>Y=2
C=1 +H=4 +O=? = C=1 +O=(2+2) +H=4
C=1 +H=4 +O=4 = C=1 +O=4 +H=4
O=4>>X=2
CH4+(2)O2 =CO2 +(2)H2O