The equilibrium constant, Kc=0.026
<h3>Further explanation</h3>
Given
1.72 moles of NOCI
1.16 moles of NOCI remained
2.50 L reaction chamber
Reaction
2NOCI(g) = 2NO(g) + Cl2(g).
Required
the equilibrium constant, Kc
Solution
ICE method
2NOCI(g) = 2NO(g) + Cl2(g).
I 1.72
C 0.56 0.56 0.28
E 1.16 0.56 0.28
Molarity at equilibrium :
NOCl :

NO :

Cl2 :

![\tt Kc=\dfrac{[NO]^2[Cl_2]}{[NOCl]^2}\\\\Kc=\dfrac{0.224^2\times 0.112}{0.464^2}=0.026](https://tex.z-dn.net/?f=%5Ctt%20Kc%3D%5Cdfrac%7B%5BNO%5D%5E2%5BCl_2%5D%7D%7B%5BNOCl%5D%5E2%7D%5C%5C%5C%5CKc%3D%5Cdfrac%7B0.224%5E2%5Ctimes%200.112%7D%7B0.464%5E2%7D%3D0.026)
Answer : The amount of carbon dioxide produced is, 197.12 grams.
Explanation : Given,
Moles of ethanol = 2.24 mole
Molar mass of carbon dioxide = 44 g/mole
The balanced chemical reaction will be,

First we have to calculate the moles carbon dioxide.
From the balanced chemical reaction, we conclude that
As, 1 mole of ethanol react to give 2 moles of carbon dioxide
So, 2.24 mole of ethanol react to give
moles of carbon dioxide
Now we have to calculate the mass of carbon dioxide.


Therefore, the amount of carbon dioxide produced is 197.12 grams.
Answer:
Either C or D
Explanation
I would go with C or D I think it is C though it seems like a better choice sorry if im wrong or give a bad answer
Answer:
The products formed are
2-methyl-3-isopropylnonan-3-ol and 2-methyloctan-2-ol
The products should be in equal ratio since an equipmolar amount of acetone and 2,4-dimethylpentan-3-one was initially present as reactants
Explanation:
Ketones reacts with gridnard reagents to form tertiary alcohol, and since acetone and 2,4-dimethylpentan-3-one are both ketones, gridnard reagent reduced both to tertiary alcohols:2-methyl-3-isopropylnonan-3-ol and 2-methyloctan-2-ol