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Butoxors [25]
3 years ago
15

Suppose a new group 5A element is discovered. Photoelectron spectroscopy (PES) reveals that its last two peaks occur at 1370 kJ/

mol and 777 kJ/mol. Calculate the average valence electron energy (AVEE) of this element.
Chemistry
1 answer:
iren2701 [21]3 years ago
5 0

Answer: The average valence electron energy (AVEE) of this element =

1014.2 KJ/ mol  or  1.0142mJ/mol.

Explanation:

The average valence electron energy =  (number of electrons in s subshell  x  Ionization energy of that subshell) + (number of electrons in p subshell  x  Ionization energy of that subshell) / total number of electrons in both subshells of the valence shells.

The 5A elements are non-metals like Nitrogen and Phosphorus with the metallic character increasing as you go down the group, So a new 5A element will have characteristics of its group with 5 valence electron in its outermost shell represented as ns2 np3

Therefore  the average valence electron energy (AVEE) of this element will be calculated as

The average valence electron energy = (2 x 1370  kJ/mol + 3 x 777 kJ/mol.) / 5

2740+2331/ 5 =5071/5

=1014.2 KJ/ mol  or  1.0142mJ/mol.

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When dipentyl ether is treated with HI, what type of reaction occurs? both SN1 and SN2 SN2 E1 SN1 E2
masha68 [24]

Answer:

SN2

Explanation:

The first step of ether cleavage is the protonation of the ether since ROH is a better leaving group than RO-.

The second step of the reaction may proceed by either SN1 or SN2 mechanism depending on the structure of the ether. Methyl and primary ethers react with HI by SN2 mechanism while tertiary ethers react with HI by SN1 mechanism. Secondary ethers react with HI by a mixture of both mechanisms.

Dipentyl ether is a primary ether hence when treated with HI, the reaction with HI proceeds by SN2 mechanism as explained above.

7 0
3 years ago
How many oxygen atoms are in 17.63 grams of CO2?
Assoli18 [71]
<span> ca. 0.4 moles. if this helps plz medal!</span>
3 0
3 years ago
Please answer asap! worth 35 points!
Gnesinka [82]

Answer:

The enthalpy of the solution is -35.9 kJ/mol

Explanation:

<u>Step 1:</u> Data given

Mass of lithiumchloride = 3.00 grams

Volume of water = 100 mL

Change in temperature = 6.09 °C

<u>Step 2:</u> Calculate mass of water

Mass of water = 1g/mL * 100 mL = 100 grams

<u>Step 3:</u> Calculate heat

q = m*c*ΔT

with m = the mass of water = 100 grams

with c = the heat capacity = 4.184 J/g°C

with ΔT = the chgange in temperature = 6.09 °C

q = 100 grams * 4.184 J/g°C * 6.09 °C

q =2548.1 J

<u>Step 4:</u> Calculate moles lithiumchloride

Moles LiCl = mass LiCl / Molar mass LiCl

Moles LiCl = 3 grams / 42.394 g/mol

Moles LiCl = 0.071 moles

<u>Step 5:</u> Calculate enthalpy of solution

ΔH = 2548.1 J /0.071 moles

ΔH = 35888.7 J/mol = 35.9 kJ/mol (negative because it's exothermic)

The enthalpy of the solution is -35.9 kJ/mol

3 0
3 years ago
Properties of elements within a blank on the periodic table change in a predicatable way from one side of the table to the other
Vitek1552 [10]

Answer: oxygen

Explanation:

7 0
2 years ago
3. At 10.0°C and 2.00 atm, the volume of the gas is 75.0 mL. If the temperature of the gas increases to
alex41 [277]

Explanation:

c.

from \\  \frac{P _{1} V _{1} }{T _{1}}  =  \frac{P _{2} V _{2}}{T _{2}} \\ \frac{2 \times 75}{(10+273)}  =  \frac{V _{2} \times 1}{(35+273)}  \\V _{2} =  \frac{2 \times 75 \times (35+273)}{(10+273) \times 1}   \\ V _{2} = 163 \: ml

6 0
2 years ago
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