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ipn [44]
3 years ago
5

If the input force on a simple machine is 2 N and the output force is 4 N, what is it’s mechanical advantage?

Physics
2 answers:
ivann1987 [24]3 years ago
7 0

Explanation:

Given that,

Input force on a simple machine, F = 2 N

The output force on a simple machines, F' = 4 N

The ratio of the output force to the input force of any simple machines is called its mechanical advantage. Mathematically, it is given by :

m=\dfrac{F'}{F}

Putting the value of F and F' in above equation. We get :

m=\dfrac{4}{2}

m = 2

So, the mechanical advantage of the simple machines is 2. Hence, this is the required solution.

Musya8 [376]3 years ago
3 0

Answer:

Mechanical advantage, m = 2

Explanation:

Given that,

The input force on a simple machine, F_i=2\ N

The output force on a simple machine, F_o=4\ N

To find,

The mechanical advantage of the simple machine.

Solution,

The ratio of the output force to the input force of any simple machines is called its mechanical advantage. Its expression is given by the below formula :

m=\dfrac{F_o}{F_i}

m=\dfrac{4}{2}

m = 2

Therefore, the mechanical advantage of the simple machines is 2.

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In air, the 57 GHz radio wave has a shorter<br> wavelength compared to the 64 GHz radio wave.
dalvyx [7]

Answer:

False

Explanation:

Higher frequency signals have shorter wavelengths. Hence, the 64 GHz signal will have a shorter wavelength than the 57 GHz signal.

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6 0
3 years ago
A step up transformer has 250 turns on its primary and 500 turns on it secondary. When the primary is connected to a 200 V and t
Zina [86]

Answer:

2000 W

Explanation:

First of all, we need to find the output voltage in the transformer, by using the transformer equation:

\frac{V_1}{N_1}=\frac{V_2}{N_2}

where here we have

V1 = 200 V is the voltage in the primary coil

V2 is the voltage in the secondary coil

N1 = 250 is the number of turns in the primary coil

N2 = 500 is the number of turns in the secondary coil

Solving for V2,

V_2 = N_2 \frac{V_1}{N_1}=(500) \frac{200 V}{250}=400 V

Now we can find the power output, which is given by

P = VI

where

V = 400 V is the output voltage

I = 5 A is the output current

Substituting,

P = (400 V)(5 A) = 2,000 W

3 0
4 years ago
The momentum of a car is 13,300 kgm/s. If it has a speed of 14 m/s, what is the mass of the car?
Tamiku [17]
By definition we have that the linear moment is
 p = m * v
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7 0
3 years ago
three girls were pushing the same car with a net force of 450 N [N48°E]. Two of the girls were pushing with forces of 310 N [N25
ElenaW [278]

The net force is the vector

∑ F = (450 N) (cos(42°) i + sin(42°) j)

and two of the forces provided by the girls are

F₁ = (310 N) (cos(115°) i + sin(115°) j)

F₂ = (250 N) (cos(285°) i + sin(285°) j)

Then the force provided by the third girl is the vector

F₃ = ∑ F - F₁ - F₂

F₃ = ((450 N) cos(42°) - (310 N) cos(115°) - (250 N) cos(285°)) i

… … … + ((450 N) sin(42°) - (310 N) sin(115°) - (250 N) sin(285°)) j

F₃ ≈ (400.722 N) i + (261.635 N) j

So, the third girl provided a force of magnitude

||F₃|| = √((400.722 N)² + (261.635 N)²) ≈ 478.572 N ≈ 480 N

pointing in a direction

arctan((261.635 N)/(400.722 N)) ≈ 33.1409° ≈ 33°

relative to East which refers to 0°; that is, 33° N of E or E33°N. Since the other forces are given relative to North or South, we can write this direction as N57°E.

So, the third girl pushed with force 480 N [N57°E].

5 0
3 years ago
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