Question

A crate is lifted vertically 1.5 m and then held at rest. The crate has weight 100 N (i.e., it is supported by an upward force of 100 N). How much work was done in lifting the crate from the ground to its final position?

Answer 1

Answer:

150 J

Explanation:

Work: This can be defined as the product of force and distance. The S.I unit of work is Joules (J)

The work done in lifting the crate = Force × distance.

W = F×d .............................. Equation 1.

Where F = force, d = distance, W = work done in lifting the crate,

Given: F = 100 N, d = 1.5 m.

Substituting these values into equation 1

W = 100(1.5)

W = 150 J.

Thus the work done in lifting the crates to that height is 150 J