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ra1l [238]
3 years ago
12

What two simple machines are found in a bike?

Physics
1 answer:
omeli [17]3 years ago
3 0
I think it's a pulley and a lever.
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Joe first focuses his attention (and his eyes) on the tree. The focal length of the cornea-lens system in his eye must be ______
nexus9112 [7]

Answer:

The correct answer is letter b. less than

Explanation:

In the attached schematic figure, the lens (lens) is initially adjusted for a given distance from the object. If the object gets closer, the image loses its sharpness. To recover it, the lens settles down, increasing convergence, that is, decreasing the focal length.

4 0
3 years ago
Read 2 more answers
Calculate the work done when: <br><br> The resultant force on a car is 22kN and it travels 2.0km.
RoseWind [281]
W=Fd
W=22,000N*(2,000m)
W=44,000,000J
6 0
3 years ago
Read 2 more answers
THE RIGHT ANSWER WILL RECEIVE A BRAINLESS AND POINTS AND THANKS!!!
poizon [28]

Answer:

391.67Hz

Explanation:

The fundamental frequency formula in string is expressed as;

Fo = V/2L

V is the velocity of the wave = 329m/s

L is the length of the string = 42cm = 0.42m

Substitute

Fo = 329/2(0.42)

Fo = 329/0.84

Fo = 391.67Hertz

Hence the  fundamental frequency of a mandolin string is 391.67Hz

4 0
3 years ago
A hot-air balloon of diameter 12 mm rises vertically at a constant speed of 15 m/sm/s. A passenger accidentally drops his camera
jeka94

To solve this problem we will apply the linear motion kinematic equations. With the information provided we will calculate the time it takes for the object to fall. From that time, considering that the ascent rate is constant, we will take the reference distance and calculate the distance traveled while the object hit the ground, that is,

h = v_0 t -\frac{1}{2} gt^2

-18 = 15*t + \frac{1}{2} 9.8*t^2

t = 3.98s

Then the total distance traveled would be

h = h_0 +v_0t

h = 18+15*3.98

h = 77.7m

Therefore the railing will be at a height of 77.7m when it has touched the ground

5 0
3 years ago
In a certain experiment, a radio transmitter emits sinusoidal electromagnetic waves of fre- quency 110.0 MHz in opposite directi
Shkiper50 [21]

To solve the problem it is necessary to take into account the concepts related to frequency depending on the wavelength and the speed of light.

By definition we know that the frequency is equivalent to,

f=\frac{c}{\lambda}

where,

c= Speed of light

\lambda = Wavelength

While the wavelength is equal to,

\lambda = \frac{2L}{n}

Where,

L = Length

n = Number of antinodes/nodes

PART A) For the first part we have that our wavelength is 110MHz, therefore

\lambda = \frac{c}{f}

\lambda = \frac{3*10^8}{11*10^6}

\lambda = 1.36m

Therefore the distance between the nodal planes is 1.36m

PART B) For this part we need to find the Length through the number of nodes (8) and the wavelength, that is,

\lambda'=\frac{2L}{n}

L = \frac{\lambda n}{2}

L = \frac{8*2.72}{2}

L = 10.90m

Therefore the length of the cavity is 10.90m

4 0
3 years ago
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