Answer:
The correct answer is letter b. less than
Explanation:
In the attached schematic figure, the lens (lens) is initially adjusted for a given distance from the object. If the object gets closer, the image loses its sharpness. To recover it, the lens settles down, increasing convergence, that is, decreasing the focal length.
W=Fd
W=22,000N*(2,000m)
W=44,000,000J
Answer:
391.67Hz
Explanation:
The fundamental frequency formula in string is expressed as;
Fo = V/2L
V is the velocity of the wave = 329m/s
L is the length of the string = 42cm = 0.42m
Substitute
Fo = 329/2(0.42)
Fo = 329/0.84
Fo = 391.67Hertz
Hence the fundamental frequency of a mandolin string is 391.67Hz
To solve this problem we will apply the linear motion kinematic equations. With the information provided we will calculate the time it takes for the object to fall. From that time, considering that the ascent rate is constant, we will take the reference distance and calculate the distance traveled while the object hit the ground, that is,



Then the total distance traveled would be



Therefore the railing will be at a height of 77.7m when it has touched the ground
To solve the problem it is necessary to take into account the concepts related to frequency depending on the wavelength and the speed of light.
By definition we know that the frequency is equivalent to,

where,
c= Speed of light

While the wavelength is equal to,

Where,
L = Length
n = Number of antinodes/nodes
PART A) For the first part we have that our wavelength is 110MHz, therefore



Therefore the distance between the nodal planes is 1.36m
PART B) For this part we need to find the Length through the number of nodes (8) and the wavelength, that is,




Therefore the length of the cavity is 10.90m