All categories

3 years ago

When Trinity pulls on the rope with her weight, Newton's Third Law of Motion tells us that the rope will _____.

Physics

2 answers:

kari74 [83]3 years ago

6 0

As we know that for every action there is equal and opposite reaction

So here it says that if we apply some external force on a system then system will exert same magnitude force on us but in opposite direction.

This is Newton's III law which is applicable in all classical situations

Now here we can see in the given situation we have given that Trinity pulls the rope with her weight so As per Newton's III law the rope will Pull Trinity by same force i.e. equal to his weight in opposite direction.

Grace [21]3 years ago

5 0

The rope will pull back against you.

You might be interested in

Pls help. This is about heat. I got the answer, just need the working

Mars2501 [29]

Answer:

See below

Explanation:

You have to heat the calorimeter to 100 C from 20 C

this will take .20 kg * 390 j /kg-C * 80 C = 6240 j

You have to heat the mass of water to boiling point (100 C ) from 20C

this will take

.50 kg * 4182 j/kg-C * 80 = 167,280 j

AND you have to add enough heat to boil off .03 kg of water:

.03 kg * (2260000 j/kg-C ) = 67,800 j

Power = joules / sec = (6240 + 167280 + 67800) / 274.8 = 878 watts

Your answer may differ just a bit for slightly different or rounded values of specific heat or heat of fusion for water .....

7 0

2 years ago

What is an intraplate quake? What causes them?

Anastasy [175]

intraplate earthquake occurs in the interior of a tectonic plate, basically its a lower version of an earth quake but just less damage. The cause of them is the two tectonic plate hitting each other or i should say sliding togather.

8 0

3 years ago

How must the height of A relate to the height of B for the skateboarder to have just enough energy to complete the loop?

KiRa [710]

Answer:

The answer is D

Explanation:

8 0

3 years ago

Read 2 more answers

It has been suggested that rotating cylinders about 10 mi long and 5.9 mi in diameter be placed in space and used as colonies. T

tekilochka [14]

Answer:

ω = 0.05 rad/s

Explanation:

We consider the centripetal force acting as the weight force on the surface of the cylinder. Therefore,

$Centripetal Force = Weight\\\frac{mv^{2}}{r} = mg\\\\here,\\v = linear\ speed = r\omega \\therefore,\\\frac{(r\omega)^{2}}{r} = g\\\\\omega^{2} = \frac{g}{r}\\\\\omega = \sqrt{\frac{g}{r}}\\$

where,

ω = angular velocity of cylinder = ?

g = required acceleration = 9.8 m/s²

r = radius of cylinder = diameter/2 = 5.9 mi/2 = 2.95 mi = 4023.36 m

Therefore,

$\omega = \sqrt{\frac{9.8\ m/s^{2}}{4023.36\ m}}\\\\$

ω = 0.05 rad/s

7 0

3 years ago

The pressure on a fluid at rest in a pipe increases by 20 Pa. How does this change in pressure affect the pressure on the fluid

timofeeve [1]

Answer:The change in pressure can affect the pressure on the fluid through the radius and diameter of the pipe.

r^² x Pressure (pa).

Therefore the narrower the other part of the pile, the greater the pressure on the fluid at such part, the wider in other part the lesser the pressure on the fluid at this part.

Explanation:

4 0

3 years ago