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BigorU [14]
3 years ago
11

In the nineteenth century, Gregor Mendel first determined some basic rules of genetics that have been observed throughout all ty

pes of life. No observations have disproved these basic rules of genetics. Charles Darwin developed the idea of biological evolution around the same time, but he was unaware of Mendel’s discoveries in genetics. Over a century later, Darwin’s idea of evolution was modified in order to incorporate Mendel’s rules of genetics along with the other evidence that Darwin had used.
What is most likely the relationship between Mendel’s rules of genetics and Darwin’s idea of biological evolution?

A.)Mendel’s genetics states laws that are now part of the theory of biological evolution.
B.)Biological evolution states laws that are part of Mendel’s theory of genetics.
C.)Mendel’s genetics replaced Darwin’s entire concept of biological evolution.
D.)Biological evolution is a law that explains why all genetics exist.
Physics
2 answers:
Dmitry_Shevchenko [17]3 years ago
9 0

Hi!


The correct option would be A) Mendel’s genetics states laws that are now part of the theory of biological evolution.


When Darwin proposed the idea of biological evolution, which revolved around the concept that favorable genes are naturally selected into a species to ensure survival, his theory was criticized as during that time there was the idea that individual traits of two parents would present themselves as a blend in the offspring.

Gregor Mendel's theory of inheritance supported Darwin's idea as it dealt with the transmission of traits in generations through entities called genes, which were present in pairs for a particular trait.


Hope this helps!

irga5000 [103]3 years ago
4 0

Answer:

a

Explanation:

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Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.
kramer

Answer:

  v_x = -6\ m/s

Explanation:

initial velocity

magnitude of velocity, v = 12 m/s

angle made of velocity with negative x-axis,θ = 60°

We need to calculate x- component of v

  v_x = v cos \theta

velocity is in negative x-direction, v = -12 m/s

now,

  v_x = -12\times cos 60^0

  v_x = -12\times 0.5

  v_x = -6\ m/s

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3 years ago
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Lisa [10]

Answer:

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Explanation:

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4 years ago
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Which has more momentum, a 2000 lb car moving at 100 km/hr or a 4000 lb truck moving at 50 km/hr ?
BabaBlast [244]

Answer:

The truck and car have the same momentum.

Explanation:

m_1 = Mass of car = 2000\ \text{lb}=2000\times0.45359237\ \text{kg}

v_1 = Velocity of car = \dfrac{100}{3.6}\ \text{m/s}

m_2 = Mass of truck = 4000\times0.45359237\ \text{kg}

v_2 = Velocity of truck = \dfrac{50}{3.6}\ \text{m/s}

Momentum of car

p_1=m_1v_1\\\Rightarrow p_1=2000\times0.45359237\times \dfrac{100}{3.6}\\\Rightarrow p_1=25199.58\ \text{kg m/s}

Momentum of the truck

p_2=m_2v_2\\\Rightarrow p_2=4000\times0.45359237\times \dfrac{50}{3.6}\\\Rightarrow p_2=25199.58\ \text{kg m/s}

Both the truck and car have the same momentum of 25199.58\ \text{kg m/s}.

8 0
3 years ago
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